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3 years ago

A man goes 150 m due east and then 200 m due north how far is he from starting point

Physics

1 answer:

grin007 [14]3 years ago

7 0

Answer:

250 m

Explanation:

Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.

Hence, sqrt(150^2+200^2) = 250 m.

Hope this helped!

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So replacing we have to

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The ratio between the two intensities would be

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The power does not change therefore it remains constant, which allows summarizing the expression to

$\frac{I_1}{I_2}=(\frac{r_2}{r_1})^2$

Re-arrange to find $I_2$

$I_2 = I_1 (\frac{r_1}{r_2})^2$

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