Question

Can anyone help me in doing this question?

Answer 1

1. No. 108 g of Ag has a lower number of atoms than 80 g of Ca.

2. The gram of $SO_3$ in 3 moles of the compound would be 240 g.

3. 1.20 x $10^{24$ atoms

4. The grams of hydrogen in 3.6 x $10^{24$ molecules of $NH_3$ would be 18 grams.

Number of atoms in compounds

According to Avogadro, 1 mole of a substance contains 6.022 x $10^{23$ molecules or atoms.

Recall that: mole = mass/molar mass

1. 108 g of Ag would be equivalent to: 108/108 = 1 mol.

80 g of Ca would be equivalent to: 80/40 = 2 mol

Since 1 mol is equivalent to 6.022 x $10^{23$ molecules or atoms, it means 80 g of Ca has twice as atoms as 108 g of Ag.

2. 3 mol sample of $SO_3$ would be equivalent to: 3 x 80 = 240 g

3. 124 g of $Na_2O$ would be equivalent to: 124/62 = 2 mol

Number of atoms = 2 x 6.022 x $10^{23$

                              = 1.20 x $10^{24$ atoms

4. 3.6 x $10^{24$ molecules of $NH_3$ would be equivalent to:

  3.6 x $10^{24$/6.022 x $10^{23$ = 6 mol of $NH_3$

$NH_3 --- > 3H^+ + N^{3-$

From the above equation, 1 mole of $NH_3$ produces 3 moles of hydrogen.  Thus,  6 moles of  $NH_3$ would be equivalent to 18 moles of hydrogen.

18 moles of hydrogen = 18 x 1

                                    = 18 g

More on the number of atoms in samples can be found here: brainly.com/question/28834341

#SPJ1