Answer:
Water is polar.
Water is an excellent solvent.
Water has a high heat capacity.
Water has a high heat of vaporization.
Water has cohesive and adhesive properties.
Water is less dense as a solid than as a liquid.
To answer your question I will use dimensional analysis, which is used by cancelling out the units. I will also use the balanced equation provided as a conversion factor.
A) First start out with the 0.300 mol of C6H12O6...
0.300 mol C6H12O6 * (2 mol CO2 / 1 mol C6H12O6) = 0.600 mol CO2
*The significant figures (sig figs) at still three, the 2 is a conversion counting number and does not count*
B) First change 2.00 g of C2H5OH to moles of C2H5OH...
The molecular mass of C2H5OH is...
2(12.01 g/mol) + 5(1.008 g/mol) + 16.00 g/mol + 1.008 g/mol = 46.07 g/mol
This can be used as a conversion factor to change grams to moles.
2.00 g C2H5OH * (1 mol C2H5OH / 46.07 g C2H5OH) = 0.0434 mol C2H5OH
Second, you can change the moles of C2H5OH to moles of C6H12O6..
0.0434 mol C2H5OH * (1 mol C6H12O6 / 2 mol C6H12O6) = 0.0217 mol C6H12O6
Third, change moles of C6H12O6 to grams...
MM = 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00 g/mol) = 180.16 g/mol
0.0217 mol C6H12O6 * (180.16 g C6H12O6 / 1 mol C6H12O6) = 3.91 g C6H12O6
C) Now I am going to put it all into one long dimensional analysis problem.
MM of CO2 = 44.01 g/mol
MM of C2H5OH = 46.07 g/mol
2.00 g C2H5OH * (1 mol C2H5OH / 46.07 g C2H5OH) * (2 mol CO2 / 2 mol C2H5OH) * (44.01 g CO2 / 1 mol CO2) = 1.91 g CO2
I hope this helped and I am sorry that I talked to much, I just didn't want to miss anything!
Answer:
B. Watermelon
Explanation:
Watermelon is the only option with a definite shape that wouldn't change if you put it in a bowl
In the space of 1 liter, methane gas (ch4) is reacted with 6 moles of water vapor according to the reaction: if at equilibrium state is obtained 4 moles of hydrogen gas, how many moles of methane gas is needed for the equilibrium reaction?
the reaction is
CH4(g) + 2H2O(g) ----> CO2(g) + 4H2 (g)
Kc = 16 / 3
Kc = [CO2] [H2]^4 / [CH4] [H2O]^2
given :
equilibrium concentration
[H2] = 4 moles
so equilibrium concentration of CO2 must be 1 mole
equilibrium concentration of H2O = 6 - 2 = 4
putting values
16 /3 = [1] [4]^4 / [CH4] [4]^2
[CH4] = 0.333 moles
so moles of CH4 required = 1.33 moles
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3
