Answer:
The function touches the damping factor
at x=
and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)=
and damping factor as y=
and y=
To find when function touches the damping factor:
For f(x)= and y=
Equating the both the equation,
x=
For f(x)= and y=
Equating the both the equation,
x=
Therefore, The function touches the damping factor x= and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=
Hence, is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
There isn't any choices given in this problem but I can give you a tip to answer these kinds of problem. When you say independent, it means that the equation cannot be algebraically altered to result to 3x + 4y = 8. So the equation 6x + 8y = 16 is not an independent equation since when you divide each side by 2 it will result to 3x + 4y =8. You get the idea. <span />
Answer:
Range: [-2, 2] {y | -2 ≤ y ≤ 2}
Step-by-step explanation:
The given function is y = 2sinx
We have to find the range of the given function.
Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]
and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]
So range of y = 2sinx is [-2, 2]
Answer:
4÷7 is 0.571428571428571
= 0.57
Step-by-step explanation:
Hope this helps!!!
