My question is BELOW so answer is pls due today

What is the volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft?

Natasha_Volkova [10]

Answer:

The volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:

5889.95 ft³

Step-by-step explanation:

We are given a base diameter of a right circular cylinder as :

d = 17.5 ft.

hence radius of cylinder i.e. r =d/2 = 8.75 ft.

height of the cylinder = 24.5 ft.

now we know that volume of cylinder i.e. V is given by :

V = πr²h

putting the value of r and h in the given formula to obtain the volume

V = 3.14×(8.75)²×24.5

= 5889.95 ft³

hence, the volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:

5889.95 ft³

3 0

3 years ago

Read 2 more answers

Which causal relationship is justifiable?

poizon [28]

Answer:

Step-by-step explanation:

Only (c) makes sense. The game draws people, which in turn means more cars and heavier traffic in the surrounding area.

3 0

3 years ago

Elena has $0.90. Kia has 10 times as much money

Vlada [557]

Answer:

Kia has ten times more money than Elena. Kia has more money that Elena.

Troy has one-tenth of the money Elena has. Troy has less money than Elena.

Step-by-step explanation:

3 0

3 years ago

Investments historically have doubled every 9 years. if you start with 2,000 investment, how much money would you have after 45

77julia77 [94]

Answer: 64,000

Equation: 2,000*2^(45/9)

4 0

3 years ago

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .