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(a) 0.0021 s, 2926.5 rad/s
The frequency of the B note is
The time taken to make one complete cycle is equal to the period of the wave, which is the reciprocal of the frequency:
The angular frequency instead is given by
And substituting
f = 466 Hz
We find
(b) 20 Hz, 125.6 rad/s
In this case, the period of the sound wave is
T = 50.0 ms = 0.050 s
So the frequency is equal to the reciprocal of the period:
While the angular frequency is given by:
(c)
The minimum angular frequency of the light wave is
so the corresponding frequency is
and the period is the reciprocal of the frequency:
The maximum angular frequency of the light wave is
so the corresponding frequency is
and the period is the reciprocal of the frequency:
(d)
In this case, the frequency is
So the period in this case is
While the angular frequency is given by