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Anika [276]
1 year ago
9

At a distance r from a charge e on a particle of mass m the electric field value is

Physics
1 answer:
mel-nik [20]1 year ago
7 0

At a distance r from a charge e on a particle of mass m the electric field value is  8.9876 × 10⁹ N·m²/C². Divide the magnitude of the charge by the square of the distance of the charge from the point. Multiply the value from step 1 with Coulomb's constant.

<h3>what is magnitude ?</h3>

Magnitude can be defined as the maximum extent of size and the direction of an object.

It is used as a common factor in vector and scalar quantities, as we know scalar quantities are those quantities that have magnitude only and vector quantities are those quantities have both magnitude and direction.

There are different ways where magnitude is used Magnitude of earthquake,  charge on an electron, force, displacement, Magnitude of gravitational force

For more details regarding magnitude, visit

brainly.com/question/28242822

#SPJ1

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Part A
Makovka662 [10]

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

p = mv

Where, m = mass

v = velocity

Put the value into the formula

p=0.0073\times0.65

p=0.004745\ kg m/s

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

p=mv

v=\dfrac{p}{m}

Put the value into the formula

v=\dfrac{3.14}{0.136}

v=23.0\ m/s

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

7 0
3 years ago
What is Newton's law of universal gravitation?
pshichka [43]
Newton's law of universal gravitation<span> states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. hope this helps =)</span>
8 0
3 years ago
Read 2 more answers
A mercury thermometer is constructed as
Tamiku [17]

Answer:

The change in height of the mercury is approximately  2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C

from which we solved for the change in volume \Delta V due to a given change in temperature \Delta T

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3

Therefore, the change in volume with a change in temperature of 36°C becomes:

\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm

8 0
3 years ago
A plank rests on top of the axles of two identical wheels. Each wheel's outer radius is 0.25 meters and each wheel's axle has ra
kaheart [24]

Answer:

<u><em>The plank moves 0.2m from it's original position</em></u>

Explanation:

we can do this question from the constraints that ,

  • the wheel and the axle have the same angular speed or velocity
  • the speed of the plank is equal to the speed of the axle at the topmost point .

thus ,

<em>since the wheel is pure rolling or not slipping,</em>

<em>⇒v=wr</em>

where

<em>v - speed of the wheel</em>

<em>w - angular speed of the wheel</em>

<em>r - radius of the wheel</em>

<em>since the wheel traverses 1 m let's say in time 't' ,</em>

<em>v_{w}=\frac{distance}{time} =\frac{1}{t}</em>

∴

⇒w=\frac{v_{w}}{r} = \frac{1}{t*0.25}

the speed at the topmost point of the axle is :

⇒v_{a}=w*r\\v_{a}=\frac{1}{t*0.25} *0.05\\v_{a}=\frac{1}{5t}

this is the speed of the plank too.

thus the distance covered by plank in time 't' is ,

⇒d=v_{a}*t\\d=\frac{1}{5t} *t\\d=\frac{1}{5} = 0.2m

8 0
4 years ago
What type of machine is wire cutter pliers?
Sonja [21]
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. The type of machine that a wire cutter pliers is classified is a simple machine. When we say simple machine, this is the type of machine that is considered basic wherein you need to apply force for it to function. Hope this helps.
3 0
3 years ago
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