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Vesna [10]
3 years ago
12

Which of the following is not a component of fitness? A. Cardiovascular fitness B. Muscular endurance C. Pulmonary endurance D.

Body composition
Physics
1 answer:
Ne4ueva [31]3 years ago
7 0

Answer:

C. Pulmonary endurance

Explanation:

I'm pretty sure it's "C" because cardiovascular and pulmonary endurance are the same thing and usually you'd hear cardiovascular more than pulmonary.

Sorry if I'm wrong!

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Which of the following simple machines is not properly identified? A. Scissors: lever B. Pizza cutter: wedge C. Screw: wheel and
GrogVix [38]

Pretty sure the answer is   C. Screw: wheel and axle

8 0
3 years ago
Which statement best describes the isothermal process? A. the temperature remains constant B. the temperature increases at a con
Veronika [31]

Answer:

The answer would be A. - the temperature remains constant

Explanation:

An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0

5 0
3 years ago
Read 2 more answers
Early psychologists were predominately all of the following except __________. A. white B. male C. European D. wealthy
yulyashka [42]

Answer: D. wealthy

Explanation: on the e2020 test its right

7 0
3 years ago
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Air (14.5 lb) undergoes a polytropic process in a closed system from p1 = 80 lbf/in2, υ1 = 4 ft3/lb to a final state where p2 =
Yanka [14]
The energy transfer in terms of work has the equation:

W = mΔ(PV)

To be consistent with units, let's convert them first as follows:

P₁ = 80 lbf/in² * (1 ft/12 in)² = 5/9 lbf/ft²
P₂ = 20 lbf/in² * (1 ft/12 in)² = 5/36 lbf/ft²
V₁ = 4 ft³/lbm
V₂ = 11 ft³/lbm

W = m(P₂V₂ - P₁V₁)
W = (14.5 lbm)[(5/36 lbf/ft²)(4 ft³/lbm) - (5/9 lbf/ft²)(11 lbm/ft³)]
W = -80.556 ft·lbf

In 1 Btu, there is 779 ft·lbf. Thus, work in Btu is:
W = -80.556 ft·lbf(1 Btu/779 ft·lbf)
<em>W = -0.1034 BTU</em>


4 0
3 years ago
The downward force produced when air flows over the winglike spoiler on a race car is an example of ___ principle
Murljashka [212]

As per bernoulli's principle

P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2

here

P_1 = pressure upwards

P_2 = pressure downwards

v_1 = velocity of air upwards

v_2 = velocity of air downwards

now from this equation we can say that the pressure difference will be

P_1 - P_2 = \frac{1}{2}\rho v_2^2 - \frac{1}{2}\rho v_1^2

now the force due to this pressure difference will be

F = (P_1 - P_2)A

so this is the above force which is given above

5 0
3 years ago
Read 2 more answers
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