Answer:
The spring constant is 3750 N/m
Explanation:
Use the following two relationships:
(Work) = (Force) x (Displacement)
(Force) = (Spring constant) x (Displacement)
=>
(Spring constant) = (Force) / (Displacement) = (Work) / (Displacement)^2
(Spring constant) = 6.0 kg.(m^2/s^2) / 0.0016 m^2 = 3750 N/m
The spring constant is 3750 N/m
Answer:
Explanation:
During the first .8 s , the elevator is under acceleration . It starts from initial velocity u = 0 , final velocity v = 1.2 m /s , time = .8 s
v = u + at
1.2 = 0 + .8 a
a = 1.2 / .8
= 1.5 m /s²
During the acceleration in upward direction , let reaction force of ground on man be R .
Net force on man = R - mg
Applying Newton's 2 nd law
R - mg = ma
R = m ( g + a )
= 72 ( 9.8 + 1.5 )
= 813.6 N .
This reaction force will be measured by spring scale , so reading of spring scale will be 813.6 N .
Hello! Assuming that the only force acting on the mass is 30N...
Fnet = 30N
Fnet = ma (mass x acceleration)
ma = 30N
a = 30N / m
a = 30N / 7kg
a = 4.2857 m/s^2
a = 4 m/s^2
I hope this helps!
