Answer:
R = -2500N
Explanation:
Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff = Ma.
Fe is the force developed by the engine: 4000N
Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.
Mass: 1000kg
Acceleration: 1.5m/s^2
Next, just plug in the values and solve.
▪4000N - Ff = (1000kg)(1.5m/s^2)
▪Ff = 1500N - 4000N
▪Ff = -2500N
R = -2500N.
The air resistance acting on the car is R = -2500N.
Answer:
Their change in momentum is the same in magnitude and opposite in direction
Explanation:
The momentum of an object is defined as:
![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
where
m is the mass of the object
v is the velocity of the object
Therefore, the change in momentum of an object is
![\Delta p = m\Delta v](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20m%5CDelta%20v)
where
is the change in velocity.
During a collision, the force experienced by an object is equal to the rate of change of momentum:
![F=\frac{\Delta p}{\Delta t}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B%5CDelta%20p%7D%7B%5CDelta%20t%7D)
where
is the duration of the collision.
According to Newton's third law of motion, the force exerted by vehicle 1 on vehicle 2 during the collision is equal (and opposite) to the force exerted by vehicle 2 on vehicle 1, so
![F_1=-F_2](https://tex.z-dn.net/?f=F_1%3D-F_2)
Which means
![\frac{\Delta p_1}{\Delta t}=-\frac{\Delta p_2}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20p_1%7D%7B%5CDelta%20t%7D%3D-%5Cfrac%7B%5CDelta%20p_2%7D%7B%5CDelta%20t%7D)
And since the duration of the collision is the same for the two vehicles, this becomes
![\Delta p_1 =-\Delta p_2](https://tex.z-dn.net/?f=%5CDelta%20p_1%20%3D-%5CDelta%20p_2)
Answer:
The photon has a wavelength of
Explanation:
The speed of a wave can be defined as:
(1)
Where v is the speed,
is the frequency and
is the wavelength.
Equation 1 can be expressed in the following way for the case of an electromagnetic wave:
(2)
Where c is the speed of light.
Therefore, ![\lamba](https://tex.z-dn.net/?f=%5Clamba)
can be isolated from equation 2 to get the wavelength of the photon.
(3)
![\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B3.00x10%5E%7B8%7Dm%2Fs%7D%7B2.00x10%5E%7B14%7Ds%5E%7B-1%7D%7D)
Hence, the photon has a wavelength of
<em>Summary: </em>
Photons are the particles that constitutes light.