Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
The answer is 648.
You have to multiply 36 by 18 to get 648
36×18 = 648
Hope that Helps :]
Hi! the answer is 2+[8x1296] because you break the 28 and the 1296 stays the same
(2, 8)
Because you cannot divide by 0, which 2 would do to the bottom.
Answer:
6/8 and 9/12
Step-by-step explanation:
Both of these fractions, when simplified, are equal to 3/4.
