Answer:
The inductance of the inductor is 35.8 mH
Explanation:
Given that,
Voltage = 120-V
Frequency = 1000 Hz
Capacitor 
Current = 0.680 A
We need to calculate the inductance of the inductor
Using formula of current
Put the value of Z into the formula
Put the value into the formula
Hence, The inductance of the inductor is 35.8 mH
Answer:
250 m
Explanation:
The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:
where
s is the distance covered
u is the initial velocity
t is the time
a is the acceleration
Assuming the car starts from rest,
u = 0
Also we know that
a = 5 m/s^2 (acceleration of the car)
t = 10 s
Substituting, we find the distance covered:
Answer:
Weight
Explanation:
"An object will float if the buoyancy force exerted on it by the fluid balances its weight, i.e. if FB=mg F B = mg . But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object."
Hope this helps! :)
Answer:
A
Explanation:
1. When the block moves across a table top, F(pulling) = - F(frictional).
Sum of this forces = 0, so the block moves with uniform speed.
2. When the block is pulled on top of the table covered with beads
F(pulling) > - F(frictional).
So, the sum of forces (∑F) is a number that is more than 0 and directed to the direction of movement.
So, a = ∑F / m is positive and constant. Speed is increasing because
v(t) = v(0)+at
a is constant and directed forward.
That means a is acceleration, and constant.
Aha! This is a fun question, likely AP Physics 1 if I'm not mistaken. This is how you solve it, you need the following equation.
Now on this question you don't need to actually use the mass and diameter of the earth as we are only
looking at the
factor of how much your weight would change, so you can just plug in some random numbers for the mass and radius. In my case I will use the original radius as being
2 meters and the original mass of the earth as being
20kg. You can actually just omit the mass of your body and the gravitational constant isn't necessary to be multiplied by because they will remain the same in both scenarios.
Original weight:
So the original weight in this circumstance is 5N. Now then if we double the mass to
40kg and the radius to
4m you will have the following.
So the original weight was 5N and after doubling the mass and radius the weight reduced to 2.5N. This means the factor which your weight would change by is .5 or decrease by 1/2.
I hope this helps you :) You can ask me if you have any additional physics questions.
