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AlexFokin [52]
3 years ago
5

The solvolysis of t-butyl bromide in methanol yields 2-methylpropene in an E1 reaction (among other products). What is the effec

t on the rate of reaction of tripling the concentration of t-butyl bromide and doubling the concentration of methanol
Chemistry
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

See explanation

Explanation:

For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.  

The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.

Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.

Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.

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4 years ago
PLS I REALLY NEED HELP DUE FODAY
Gekata [30.6K]

<u>Answer:</u> The equilibrium constant for the reaction is 54.47

<u>Explanation:</u>

The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term K_{eq}

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H_2+I_2\rightleftharpoons 2HI

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Putting values in above expression, we get:

K_{eq}=\frac{(1.3544\times 10^{-2})^2}{(4.5647\times 10^{-3})(7.378\times 10^{-4})}\\\\K_{eq}=54.47

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3 years ago
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