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AlexFokin [52]
3 years ago
5

The solvolysis of t-butyl bromide in methanol yields 2-methylpropene in an E1 reaction (among other products). What is the effec

t on the rate of reaction of tripling the concentration of t-butyl bromide and doubling the concentration of methanol
Chemistry
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

See explanation

Explanation:

For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.  

The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.

Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.

Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.

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Combustion of hydrocarbons such as propane ( C3H8 ) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's
Naddika [18.5K]

Answer:

1. C₃H₈(g) + 5O₂ (g)  → 3CO₂ (g) + 4H₂O (g)

2. The volume of CO₂ produced is 238 l.

Explanation:

Hi there!

The chemical equation is the following:

C₃H₈(g) + 5O₂ (g)  → 3CO₂ (g) + 4H₂O (g)

The molar mass of propane is calculated as follows:

mass of 1 mol carbon = 12 g

mass of 1 mol hydrogen = 1 g

mass of 1 mol propane 3 · (12 g) + 8 · (1 g) = 44 g

If we have 150 g of propane, we will have (150 g · 1 mol / 44 g) 3.4 mol propane.

Looking at the chemical equation, notice that 1 mol propane produces 3 mol CO₂. Then 3.4 mol of propane will produce:

(3.4 mol C₃H₈ ·  3 mol CO₂ / mol C₃H₈ ) 10.2 mol CO₂

Using the Ideal Gas Law we can obtain the volume of CO₂ produced:

P · V = n · R · T

Where:

P = pressure.

V = volume

n = number of moles.

R = gas constant (0.082 atm · l / ( K · mol))

T = temperature in kelvin.

V = n · R · T / P

V = 10.2 mol · 0.082 atm · l/ (K mol) · 285 K / 1 atm

Notice that 12 °C = 273  + 12  = 285 K

V = 238 l

The volume of CO₂ produced is 238 l.

Have a nice day!

7 0
4 years ago
A chemist prepares a solution by adding 258 mg of K2Cr2O7 (MW = 294.19 g/mol ) to a volumetric flask, and then adding water unti
Maksim231197 [3]

Answer: Molarity of the prepared solution is 1.75\times 10^{-3}mole/L

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{0.258g}{294.19g/mol}=8.77\times 10^{-4}mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{8.77\times 10^{-4}moles\times 1000}{500ml}=1.75\times 10^{-3}mole/L

Thus molarity of the prepared solution is 1.75\times 10^{-3}mole/L

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An ice cube at 0 degrees Celsius is heated until it melts and the water reaches 20 degrees Celsius. The amount if heat needed fo
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Answer:

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Explanation:

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What is the mass of 5.31×1021 platinum atoms?
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<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

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