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3 years ago

The four fundamental types of organic molecules are nucleic acids, proteins, lipids, and ________.

Physics

2 answers:

Elis [28]3 years ago

5 0

Answer:

Carbohydrates

Explanation:

Organic compounds are made of four fundamental type organic molecules which also called biological macro molecules. These fundamental types molecules are

1. Nucleic Acids

2. Proteins

3. Lipids

4. Carbohydrates

Macro molecules are made of single unit called monomer and these monomer are joined covalent bonds to form larger polymers.

notka56 [123]3 years ago

4 0

The other of the four organic molecules is carbohydrates.
All four of them are:
Nucleic Acids (DNA and RNA stuff)
Proteins
Lipids
& Carbohydrates

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A certain ocean wave has a frequency of 0.07 hertz and a wavelength of 10 meters. what is the wave's speed? a 0.07 m/s

Elis [28]

V=f*wavelength
v=0.07hz*10m
v=0.7 m/s

8 0

3 years ago

g A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 ra

Setler [38]

Answer:

The angular acceleration of the wheel is 15.21 rad/s².

Explanation:

Given that,

Time = 5 sec

Final angular velocity = 96.0 rad/s

Angular displacement = 28.0 rev = 175.84 rad

Let $\alpha$ be the angular acceleration

We need to calculate the angular acceleration

Using equation of motion

$\theta=\omega_{i} t+\dfrac{1}{2}\alpha t^2$

Put the value in the equation

$175.84=\omega_{i}\times 5+\dfrac{1}{2}\times\alpha\times(5)^2$

$175.84=\omega_{i}\times 5+12.5\alpha$ ......(I)

Again using equation of motion

$\omega_{f}=\omega_{i}+\alpha t$

Put the value in the equation

$96.0=\omega_{i}+\alpha \times 5$

On multiply by 5 in both sides

$480=\omega_{i}\times 5+\alpha\times 25$ ....(II)

On subtract equation (I) from equation (II)

$480-175.84=\alpha(25-5)$

$304.16=\alpha\times20$

$\alpha=\dfrac{304.16}{20}$

$\alpha=15.21\ rad/s^2$

Hence, The angular acceleration of the wheel is 15.21 rad/s².

5 0

3 years ago

You apply the brakes of your car abruptly and your book starts sliding off the front seat. Three observers sitting in the car ex

krek1111 [17]

Answer:

All the observers are correct.

Explanation:

This is simply a problem of reference frames from which the motion of the book is being viewed by the various observers.

From their various reference frames, they are all correct.

Observer A must be in the inertial reference frame.

<em>Observers who can explain the behavior of the book and the car by using the relationship between the sum of the forces and changing velocity are said to be observers in inertial reference frames.</em>

This is clearly shown by what observer A noticed. There was a relative motion between the book and the car as she pointed out, making her to be in an inertial reference frame.

<em>Similarly, observers in inertial reference frames can also explain the changes in velocity of objects by considering the forces exerted on them by other objects.</em>

This is shown by observer B as he is able to notice how the force of the car affects the velocity of the book.

Observer C is actually in a non-inertial reference frame, as newtons law of force motion relationship are no longer observed. This occurs in the non inertial reference frame.

7 0

3 years ago

How long does it take to do 300 Joules of work with 10 watts of power? 30 sec 20 sec .03 sec .30 sec

Oksana_A [137]

Answer:

Explanation:

Power=work /time

10watts=300J/time

Time =30 sec

4 0

3 years ago

A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at

MAVERICK [17]

Answer:

A) 2.5

Explanation:

Extracting vital information from the question;

speed upstream = (v-3)mile/hr, distance traveled = 90 mile, speed downstream = (v+3), time for downstream in hours = t while time for upstream = t + 0.5 hr since the upstream journey is half hour longer.

speed = distance / time = 90 / (t + 0.5)

( v - 3) = 90 / ( t + 0.5)

cross multiply

(v-3) (t + 0.5) = 90 equation (1) for upstream motion

( v+3) = 90 / t

cross multiply

t(v+3) = 90 equation (2) for downstream motion

make v subject of the formula in equation 2

vt + 3t = 90

vt = 90 - 3t

divide both side by t

vt/t = (90 - 3t) / t

v = (90 - 3t) / t

substitute for t in equation 1

(( 90 - 3t) / t) - 3) (t + 0.5) = 90

solve through finding l.c.m ( lowest common multiple)

(90 - 3t - 3t)/ t (t + 0.5) = 90

(( 90 - 6t ) / t )(t + 0.5) = 90

open the brackets and cross multiply

90t + 45 - 6t² - 3t = 90 t

rearrange and collect the like terms

- 6t² - 3t + 45 = 90t - 90t

- 6t² - 3t + 45 = 0 multiply both side by -1

6t² + 3t - 45 = 0

divide both side by 3

2t² + t - 15 = 0

factorize the expression by multiplying - 15 by 2t² = - 30t²

find factors of - 30t² that adds to t = 6t × (-5t)

replace t with (+6t - 5t) in the equation

2t²+ 6t - 5t - 15 = 0

factorize

2t ( t + 3) - 5 ( t + 3) =0

(2t -5)(t + 3) = 0

2t - 5 = 0 or t + 3 = 0

2t = 5 or t = -3

divide through 2

2t / 2 = 5/ 2 = 2.5 or t = -3 since time cannot be negative

them t = 2..5 seconds

3 0

3 years ago