Answer:
23.5 mV
Explanation:
number of turn coil 'N' =22
radius 'r' =3.00 cm=>
0.03m
resistance = 1.00 Ω
B= 0.0100t + 0.0400t²
Time 't'= 4.60s
Note that Area'A' = πr²
The magnitude of induced EMF is given by,
lƩl =ΔφB/Δt = N (dB/dt)A
=N[d/dt (0.0100t + 0.0400 t²)A
=22(0.0100 + 0.0800(4.60))[π(0.03)²]
=0.0235
=23.5 mV
Thus, the induced emf in the coil at t = 4.60 s is 23.5 mV
Answer:
d) 0 V
Explanation:
It can be showed that the potential due to a point charge q, to a distance d from the charge, can be expressed as follows:

where k = 
As the potential is an scalar, and is linear with the charge, we can apply the superposition principle, which means that we can find the potential due to one of the charges, as if the other were not present.
By symmetry, all four charges are at the same distance from the center, so we can write the total potential, as follows:

where d, is the semi-diagonal of the square, that we can find applying Pythagorean theorem, as follows:

Replacing by the values in (1) we have:

which is equal to the option d).
Answer:
The slope is 0.5
Explanation:
It increases so it is positive and it increases by half a block each time so 0.5.
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Answer:
The mmf required is
×
A
Explanation:
The Magnetomotive force (mmf) is given by the formula below

where
is the Magnetomotive force (mmf)
is the Magnetic field strength
is the magnetic length
The magnetic permeability μ is given by
μ = 
Where
is the Magnetic flux density
and
is the Magnetic field strength
From the question,
= 1.2Wb/m^2
μ = 1600m
From μ = 
∴
μ

×
A/m
Now, for the Magnetomotive force (mmf)

From the question
= 1.5 m
∴
×
× 
×
Hence, The mmf required is
×
A