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2 years ago

There is a constriction in a clinical thermometer give reasons

Physics

1 answer:

Marianna [84]2 years ago

5 0

There is a constriction made in a clinical thermometers.
As constriction stops the mercury inside the thermometer to drop back towards the bulb of thermometer.
So there is constriction used in clinical thermometers to prevent usage of alcohol or mercury into bulb

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Is it true muscle mass affects someones flexibility

guapka [62]

It is very very true

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4 years ago

What is the pendulum length whose period is 2.0s ?

Mashutka [201]

$Formula\ for\ period:\\\ T=2 \pi \sqrt{\frac{L}{g}}\\\ g-gravity=9,8 \frac{m}{s^2} ,\ L-pendulum \ length \\\\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\\\\ \frac{T^2}{2 \pi }*g=L\\\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m$ $T=2 \pi \sqrt{\frac{L}{g}} \\
 \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\
 \frac{T^2}{2 \pi } = \frac{L}{g} \\
 \frac{T^2}{2 \pi }*g=L\\
L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m
$

7 0

3 years ago

A 4kg bird is flying with a velocity of 4 m/s. What is its kinetic energy?

Yanka [14]

Kinetic energy = 32 J

8 0

3 years ago

A meter stick is held vertically above your hand, with the lower end between your thumb and first finger. On seeing the meter st

inessss [21]

Answer:

$t=0.193s$

Explanation:

What is said is that the meter fell d=18.3cm=0.183m under the action of gravity. We can use the formula for accelerated motion:

$d=v_0t+\frac{at^2}{2}$

Since it departed from rest it will mean that:

$d=\frac{at^2}{2}$

So our time will be:

$t=\sqrt{\frac{2d}{a}}$

Which for our values is:

$t=\sqrt{\frac{2(0.183m)}{(9.81m/s^2)}}=0.193s$

7 0

3 years ago

An ac generator has a maximum emf output of 150 V. What is the rms current in the circuit when the generator is connected to a 3

natima [27]

This is an insidious question. Quite frankly, I would not have
expected to see it here on Brainly. But I'm ready to play the
cards that you have dealt me.

None of the choices offered is a correct solution.

If the output of the AC generator is nice and sinusoidal, and
its maximum (peak) emf is 150 volts, then its RMS emf is

   (1/2) (150) (√2) = 106.07 volts.

The resistor's dissipation is

   Power = (current) x (voltage) .

If the resistor is dissipating its full rated 35W, then

   35W = (current) x (106.07 V)

Divide each side by 106.07 V:

   RMS Current = (35W) / (106.07 V) = 0.33 Ampere .
_________________________________________

Looking over the choices offered . . .

The largest choice ... 3.1 A ... is the current in a resistor
that is dissipating 35W if the voltage is

   (35W / 3.1A) = 11.29 volts .

The smallest choice ... 1.2 A ... is the current in a resistor
that is dissipating 35W if the voltage is

   (35W / 1.2A) = 29.17 volts .

Whatever you meant the so-called "150 V" of the generator
to represent ... whether the RMS sinusoidal, peak sinusoidal,
peak square-wave, RMS square-wave, DC, average, etc. ...
none of the choices for current, in combination with any of these
generators, would dissipate 35W.

3 0

3 years ago

There is a constriction in a clinical thermometer give reasons​

There is a constriction in a clinical thermometer give reasons