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3 years ago

13

You are riding in an airplane that is moving at a speed of 600 km/h. If you walk from the FRONT of the plane TOWARD the BACK of

the plane at a speed of 1 km/h, your speed RELATIVE TO THE GROUND is

1 answer:

MatroZZZ [7]3 years ago

5 0

Answer:

600km/h as u are on a platform moving at the speed of 600 km/h where u are moving in relativity to the plane it's self.

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Need help with this worksheet. Very short

attashe74 [19]

Answer:

In the grapher: The stops are marked with a flat line, velocity with a diagonal line, and acceleration with a curve.

Average speed= Total distance/Total time

Explanation:

6 0

2 years ago

Nicole throws a ball straight up. Chad watches the ball from a window 6.10m above the point where Nicole released it. The ball p

solong [7]

Answer:

$v=16.234m/s$

Explanation:

Given data

Distance S=6.10 m

Initial Speed u=12.0 m/s

To find

Final Speed v

Solution

From third equation of motion we know that:

$v^{2}-u^{2}=2aS$

where

v is final velocity

u is initial velocity

a is acceleration

S is distance

Substitute the given values to find v

$v^{2}=u^{2}+2aS\\v^{2}=(12.0m/s)^{2} +2(9.8m/s^{2} )(6.10m)\\v^{2}=263.56\\ v=\sqrt{263.56}\\ v=16.234m/s$

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2 years ago

Explain how atomic interactions determine a material to be transparent and opaque?

motikmotik

Answer:

Explanation below.

Explanation:

It should be understood that transparency is caused through or by the transmission of light waves. This means that, If or when the energy known as the vibrational energy of a light wave is passed through the object, then the object appears clear, or transparent. And when or If the energy only causes vibrations in the surface before reflecting off the object, then the object will appear opaque, that is nontransparent.

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2 years ago

One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force f is applied to the other end of th

Vlada [557]

For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

$F\times L = mg \times \frac{L}{2}$

here weight will act at mid point of door so its distance is half of the total distance where force is applied

here we know that

$mg = 145 N$

now we will have

$F = \frac{mg}{2}$

$F = \frac{145}{2} = 72.5 N$

so our applied force is 72.5 N

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3 years ago

When driving across Death Valley in the summertime, it is recommended that you release some air from your tires before making th

ch4aika [34]

Hot air rises ya fool ya fool

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2 years ago

Read 2 more answers