Answer:
A pipe has a length of 1.15 m.
a) Determine the frequency of the first harmonic if the pipe is open at each end. The velocity of sound in air is 343 m/s. Answer in units of Hz
b) What is the frequency of the first harmonic if the pipe is closed at one end?
Answer in units of Hz
Explanation:
- neon signs
- fireworks
- rockets during the ascent
- meteors
- fireflies
- stars
Answer:
Vx = 35 x cos(13deg)
Vy = 35 x sin(13deg) - gt
(g is acceleration due to gravity =~9.8 meter/second^2, t is time in second)
Explanation:
The tiger leaps up, then x and y component of its velocity are:
Vx = Vo x cos(alpha)
Vy = Vo x sin(alpha) - gt
(Vo is tiger's initial velocity, alpha is angle between its leaping direction and horizontal plane)
Hope this helps!
Answer:
0.0065 m³
Explanation:
Apparent weight = weight − buoyancy
32 N = 96 N − (1000 kg/m³) (9.8 m/s²) V
V = 0.0065 m³
Answer:
Explanation:
In wheel and axle. …with the system is the velocity ratio, or the ratio of the velocity (VF) with which the operator pulls the rope at F to the velocity at which the weight W is raised (VW). This ratio is equal to twice the radius of the large drum divided by the difference…
