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3 years ago

What is the weight of an object with a mass of 6.0 kg on Earth?

Physics

2 answers:

Rom4ik [11]3 years ago

6 0

Weight = Mass × The gravitational acceleration of the planet

Earth's gravitational acceleration ≅ 9.81 m/s²

Weight = 6 × 9.81 ≅ 58.86 N

gregori [183]3 years ago

3 0

<h2>since weight is measured in newtons, convert the 6 kg to newtons</h2><h3>the formula to convert is kg x 9.807 = N</h3>

6 x 9.807
= 58.842 N

hope that helps :))

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What was the first manmade satellite put into orbit

Nataly_w [17]

The Soviet Union's Sputnik 1, it was launched October 4th 1957.

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3 years ago

Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di

Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, $u=20m/s$

And the mass of the car is, $m=1000 kg$

The total distance covered by the car before stop, $s=45m$

And the final speed of the car is, $u=0m/s$

Now initial kinetic energy is,

$KE_{i}=\frac{1}{2}mu^{2}$

Substitute the value of u and m in the above equation, we get

$KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J$

Now final kinetic energy is,

$KE_{f}=\frac{1}{2}mv^{2}$

Substitute the value of v and m in the above equation, we get

$KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J$

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

$F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN$

Here, the force is negative because the force and acceleration in the opposite direction.

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3 years ago

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Svetradugi [14.3K]

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3 years ago

Give Example of mental flexibility

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Answer:

If you ring the doorbell and no one opens the door, you'll infer that no one is home rather than continuing to ring the doorbell to an empty house. Being able to understand this and look for another solution is another example of mental flexibility.

Explanation:

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3 years ago

If 35 J of work was performed in 70 seconds, how much power was used to do this task?

Irina18 [472]

$P = w \times delta \: T$
P = Power
W = Work
Delta T = Change of Time

So:
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Delta T = 70 secs
W = ?

$P = 35 \div 70 \\ P = 0.5 \: watts$

* Joule/Sec = Watt

Answer: The power used to do this task was 0.5 Watts.

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3 years ago