What is the direction of the frictional force?
Answer:
Direction of friction is always opposite to relative motion
Explanation:
Friction always resist the relative motion of two surface so it is always opposite to the direction of relative velocity
What is the direction of the normal force?
Answer:
It is perpendicular to the contact plane
Explanation:
Normal force is the perpendicular force which is always at 90 degree with the contact surface
How does the frictional force depend on the normal force?
Answer:
![F_f = \mu F_n](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20F_n)
Explanation:
Friction force is directly proportional to the normal force so we can say it is given as
![F_f = \mu F_n](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20F_n)
Let the x-axis be parallel to the incline and the y-axis rise from the incline at a right angle. By Newton's second law, if there is no acceleration in the y-direction (perpendicular to the plane), what must be the magnitude of the normal force?
Answer:
![F_n = mg cos\theta](https://tex.z-dn.net/?f=F_n%20%3D%20mg%20cos%5Ctheta)
Explanation:
Normal force is equal to the component of the weight opposite to the direction of normal force
![F_n = mg cos\theta](https://tex.z-dn.net/?f=F_n%20%3D%20mg%20cos%5Ctheta)
Use Newton's second law and the x-components of the forces to find the acceleration. m/s2
Answer:
![a = gsin\theta](https://tex.z-dn.net/?f=a%20%3D%20gsin%5Ctheta)
Explanation:
As we know that
![F_{net} = ma](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20ma)
![mg sin\theta = ma](https://tex.z-dn.net/?f=mg%20sin%5Ctheta%20%3D%20ma)
![a = gsin\theta](https://tex.z-dn.net/?f=a%20%3D%20gsin%5Ctheta)