The change in electric potential energy is given by:
ΔU = ΔVq
ΔU = change in PE, ΔV = potential difference, q = charge
Given values:
ΔV = 50V - 20V = 30V, q = 0.14C
Plug in and solve for ΔU:
ΔU = 30(0.14)
ΔU = 4.2J
Answer:
1 st question: Control variable
2nd question: random variable
3rd question: if the two objects are dropped from the same height they will hit the ground at the same time
Answer:
v = 40 m / s
Explanation:
Let's use the expressions for accelerated motion
v = v₀ + a t
where vo is the initial velocity, at the acceleration and t is the time.
as the body starts from rest its initial velocity is zero
v = 0 + at
let's calculate
v = 8 5
v = 40 m / s