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3 years ago

What are two examples of common units for each of the above measurements

Physics

1 answer:

kap26 [50]3 years ago

3 0

Density: g/mL, kg/cubic meter

Volume: L, teaspoon

Mass: g, MeV/sq. C

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The force required to stretch a Hooke’s-law spring varies from 0 N to 63.5 N as we stretch the spring by moving one end 5.31 cm

Alika [10]

Answer:

Force constant will be 1195.85 N/m

Work done will be 1.6859 J

Explanation:

We have given the force, F = 63.5 N

Spring is stretched by 5.31 cm

So x = 0.0531 m

Force is given , F = 63.5 N

We know that force is given by $F=kx$

So $63.5=k\times 0.0531$

k = 1195.85 N/m

Now we have to find the work done

We know that work done is given by

$W=\frac{1}{2}kx^2=\frac{1}{2}\times 1195.85\times 0.0531^2=1.6859J$

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2 years ago

¿A qué clase social pertenecen?

Genrish500 [490]

Answer:

Explanation:

5 0

2 years ago

Contrast the behavior of a water wave that travel by a stone barrier to a sound wave that travels through a door

charle [14.2K]

Explanation:

here the file has everything

8 0

2 years ago

Two objects experienced the same displacement in the same amount of time. The two objects must have the same -

nikdorinn [45]

If two object experiences the same displacement at the same time, the two objects must have the same average velocity.

The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

$avg. \ velocity = \frac{\Delta \ displacement }{\Delta \ time} \\\\V = \frac{\Delta \ x}{\Delta t}$

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

$\frac{\Delta x_1}{\Delta t_1} = \frac{\Delta x_2}{\Delta t_2} = V_{avg}$

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.

Learn more here: brainly.com/question/23856383

6 0

2 years ago

A boat heads due North for 3.00 km to reach a red buoy. It then changes direction and heads in a direction of 30.0 degrees South

Helga [31]

Position of B :

x = 4.66*cos 30 = 4.036

y = 3-4.66*sin 30 = 3-2.33 = 0.67

BC = √y^2+(x-1)^2 = √0.67^2+3.036^2 = 3.109

heading = arctan y/(x-1) = arctan 0.67/(3.036) = 12.44° south of west

hope this helps :)

6 0

3 years ago