All categories

2 years ago

3-2|x+4|+3=1 the answer for this

Mathematics

1 answer:

blagie [28]2 years ago

7 0

Answer:

x={-3/2,-13/2}

Step-by-step explanation:

3-2|x+4|+3=1

-2|x+4|+6=1

-2|x+4|=-5

|x+4|=5/2

x+4=5/2

x+4=-5/2

x=5/2-4

x=-3/2

x=-5/2-4

x=-13/2

You might be interested in

3n+75=50+2n please help righting more

alexandr1967 [171]

Answer: n = -25

Step-by-step explanation:

you would need to get N by itself so you would subtract 2n from both sides and that would bring you to n+75=50 and then you would need to subtract 75 from both sides and that leads you to n=-25

5 0

2 years ago

Alan thinks of a number. he squares it, then takes away 5, next multiplies it by 4, takes away 7, divides it by 3 and finally ad

Karolina [17]

He started with 3. 3 X 3 = 9. 9 - 5 = 4. 4 X 4 = 16. 16 - 7 = 9. 9 divided by 3 = 3. 3 + 6 = 9.

3 0

3 years ago

Read 2 more answers

Multiply: 4x * root(3, 4x ^ 2) * (2 * root(3, 32x ^ 2) - x * root(3, 2x))

Salsk061 [2.6K]

Answer:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

Step-by-step explanation:

We want to

$4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} } - x \sqrt[3]{2x} )$

We expand to obtain:

$4x \sqrt[3]{4 {x}^{2} } \times 2 \sqrt[3]{32 {x}^{2} } -4x \sqrt[3]{4 {x}^{2} } \times x \sqrt[3]{2x} )$

We now simplify

$8x \sqrt[3]{4 {x}^{2} \times 32 {x}^{2} } -4 {x}^{2} \sqrt[3]{4 {x}^{2} \times 2x}$

We multiply the radicand

$8x \sqrt[3]{64 \times {x}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{8 {x}^{3}}$

$8x \sqrt[3]{ {(4x)}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{{(2x)}^{3}}$

We take cube root to get:

$8x \times 4x\sqrt[3]{ 2x } -4 {x}^{2} \times 2x$

We multiply out to get:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to the following complex fraction? 2 minus StartFraction 1 Over y EndFraction divided by 3 StartF

Leya [2.2K]

The equivalent fraction to the given complex fraction is $\frac{2y-1}{3y+1}$ .

Given expression,

$\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} } } \\$

We have to find the equivalent fraction of $\frac{2-\frac{1}{y} }{3+\frac{1}{y} } } \\$ .

On solving,

$\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} } } =\dfrac{\frac{2y-1}{y} }{\frac{3y+1}{y} }$

Eliminating y from numerator and denominator we get,

$\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} } } =\dfrac{2y-1} {3y+1} }$

Hence the required expression is $\frac{2y-1}{3y+1}$ .

For more details follow the link:

brainly.com/question/17912

8 0

2 years ago

Read 2 more answers

Find the equation of the line parallel to 2y-3x= 4 and passing through the point (6,7)

frutty [35]

Answer:

We have equation of a line:

2y - 3x = 4 => y = (3/2)x + 4

The equation of the line that is parallel to above line and passes through the point (6, 7) would have form y = ax + b, and

a = 3/2

6a + b = 7

=> b = 7 - 6a = 7 - 6 x 3/2 = 7 - 9 = -2

=> The equation of that line: y = (3/2)x - 2

Hope this helps!

7 0

2 years ago

3-2|x+4|+3=1 the answer for this​

3-2|x+4|+3=1 the answer for this