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strojnjashka [21]
3 years ago
8

Is 4x + 53 = y a function or not a function?

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer:

I'm pretty sure its a function sorry if i'm wrong.

Step-by-step explanation:

pls mark brainliest

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Find the inner product for (8,4)(2,4)and state whether the vectors are perpendicular.
sp2606 [1]

Answer: C 32;no

Step-by-step explanation:

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7 0
4 years ago
What angle is supplementary to ABE?
____ [38]
It depends on the shape.Obtuse if longer than 90 degrees,acute if smaller than 90 degrees ,and right angle if exactly 90 degrees
4 0
3 years ago
What is 0.426 divided by 0.2
madreJ [45]
0.426 / 0.2
4.26 / 2
2.13
3 0
3 years ago
Someone Help? Im confuzzled
cupoosta [38]

Answer: 16π

Step-by-step explanation:

First, solve for total area:

A = πr^2

A = π(8^2) = 64π

Then, find 1/4 of the area of the whole (since this is only a quarter circle)

A/4 = (64π)/4 = 16π

3 0
3 years ago
Let f be a differentiable function such that f(3) = 2 and f'(3) = 5. If the tangent line to the graph of f at x = 3 is used to f
Marina86 [1]
The linear approximation to f(x) centered at x=a is

f(x)\approx f(a)+f'(a)(x-a)

What this means is that you can use the tangent line to f(x) at x=a to get a decent approximation of f(x) at some other value of x to within a certain degree of accuracy depending on how close this value x is close to a. (Note that when x=a, the approximation is exact; f(a)=f(a).)

So what you're asked to do is find an approximate value of a zero of f(x) near a=3. That is to say, you're looking for some value c such that f(c)=0, but all you have at your disposal is the linear approximation to the function.

f(x)\approx f(3)+f'(3)(x-3)
f(x)\approx2+5(x-2)
f(x)\approx5x-8

You know that if c is a zero of f, then f(c)=0, so you get

f(c)=0\approx5c-8

Solving for c, you find

0=5c-8\implies 5c=8\implies c=\dfrac85=1.6

This means that an approximate zero of f(x) is x=1.6.
5 0
3 years ago
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