Answer:
88.1 N
Explanation:
As shown in the free body diagram attached to the question, the only forces acting on the inner block include in the required vertical direction.
- Its Weight.
- Frictional forces as a result of the Two compression forces.
If the block is not to slip off, the weights must match the two frictional forces
Let the compressive forces be F and frictional force be Fr
Fr = μ F
Sum of force acting on the inner block in the y-direction
Fr + Fr - W = 0
μ F + μ F = mg
2 μF = 118
2(0.67) F = 118
F = 118/1.34
F = 88.1 N
Each of the compression forces is 88.1 N
Hope this Helps!!!
Answer:
Part a)
Time to reach the maximum height is given as
B)
Maximum height of the bullet is
C)
Horizontal range of the bullet is
Part d)
Final velocity of the bullet is v = 600 m/s at 30 degree
Explanation:
A) As we know that velocity of the bullet is
v = 600 m/s
So we have
Now time to reach the maximum height is given as
B) As we know that the object have zero final speed in y direction
C)
Now the horizontal displacement of the object in total time of flight is known as range of projectile
So we have
Part d)
As we know that the final height is same as that of initial So it will strike the ground at same velocity as that of initial velocity
So we have
v = 600 m/s at 30 degree
Answer:
Velocity
Explanation:
the speed of something in a given direction
I think the vehicle relation to the hearer is : Past the hearer
Have you ever walk when a motor cycle run past you ? You will notice that you will hear less sound as the motor cycle goes further
Hope this helps
Answer:
12.68 m/s.
Explanation:
Equations of motion:
i. S = vi*t + 1/2 * a*(t^2)
ii. vf = vi + a*t
iii. vf^2 = vi^2 + 2a*S
Where, vf = final velocity
vi = initial velocity
S = distance travelled
a = acceleration due to gravity
t = time taken
Given:
vi = 0 m/s
S = 8.2 m
vf = ?
a = 9.81 m/s^2
Using iii. Equation of motion,
vf^2 = vi^2 + 2a*S
= 2 * 9.81 * 8.2
= 160.884
vf = sqrt (160.884)
= 12.68 m/s.