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34kurt
3 years ago
8

Iron atoms have been detected in the sun's atmosphere, some with many of their electrons stripped away. What is the net electric

charge (in coulombs) of an iron atom with 26 protons and 12 electrons
Physics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

the net electric charge of the iron atom is 2.24 × 10⁻¹⁸ C

Explanation:

Given the data in the question;

we know that neural iron atoms should have same number of protons and electrons i.e 26 and 26 but in the sun's atmosphere, many of their electrons stripped away.

so; we have 26 protons and 12 electrons, meaning ( 26-12=14) 14 electrons have been stripped away.

when we loss electron, we gain positive charge

so, the Net charge of the iron atom of with 26 protons and 12 electrons will be;

q = 26 ( proton charge) + 12( electron charge )

we know that; a singular proton has a charge of 1.6×10⁻¹⁹ C

protons carry negative charge while electrons carry negative

we substitute

q = 26 ( 1.6×10⁻¹⁹ ) + 12( -1.6×10⁻¹⁹  )

q = 2.24 × 10⁻¹⁸ C

Therefore, the net electric charge of the iron atom is 2.24 × 10⁻¹⁸ C

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zysi [14]

Answer:

d = 3.19 km

direction is given as

\theta = 41.2 degree South of West

Explanation:

Part b)

displacement is given as

d_1 = 3.1 \hat j

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d_3 = 5.2(-\hat j)

now we will have

d = d_1 + d_2 + d_3

d = 2.4 \hat i + (3.1 - 5.2)\hat j

d = 2.4 \hat i - 2.1 \hat j

total displacement is given as

d = \sqrt{2.4^2 + 2.1^2}

d = 3.19 km

direction is given as

tan\theta = \frac{-2.1}{2.4}

\theta = 41.2 degree South of West

3 0
4 years ago
An object will sink in a liquid if the density of the object is greater than that of the liquid. The mass of a sphere is 9.83 g.
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5 0
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8 0
2 years ago
Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen
Stella [2.4K]

Answer:

1.196 μm

Explanation:

D = Screen distance = 3 m

\lambda = Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

tan\theta=\frac{y}{D}\\\Rightarrow \theta=tan^{-1}{\frac{y}{D}}\\\Rightarrow \theta=tan^{-1}{\frac{4.84\times 10^{-3}}{3}}\\\Rightarrow \theta=0.09243\ ^{\circ}

sin\theta=\frac{\lambda}{d}\\\Rightarrow d=\frac{\lambda}{sin\theta}\\\Rightarrow d=\frac{598\times 10^{-9}}{sin0.09243}\\\Rightarrow d=0.00037066\ m

For first dark fringe

dsin\theta=\frac{\lambda'}{2}\\\Rightarrow \lambda'=2dsin\theta\\\Rightarrow \lambda'=2\times 0.00037066\times sin0.09243\\\Rightarrow \lambda'=1.196\times 10^{-6}\\\Rightarrow \lambda'=1.196\ \mu m

Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm

3 0
3 years ago
A student walks a distance of 3 km in 20 minutes calculate his average speed
serg [7]

Answer:

His average speed is 0.15 kilometer per minute or 2.5 meters per second.

Explanation:

average speed = distance/time

x = 3 km/20 minutes

x = 0.15

—

x = 3000 m/1200 s

x = 2.5

4 0
3 years ago
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