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2 years ago

Why does a lone pair of electrons occupy more space around a central atom than a bonding pair of electrons?

Physics

1 answer:

Inessa [10]2 years ago

5 0

Answer:

The lone pair of electrons occupy more space because the electrostatic force becomes weaker.

Explanation:

When there is a bond pair of electrons in the 2 positively charged the atomic nuclei draw the electron density towards them, thereby reducing the bond diameter.

In the case of the lone pair, only 1 nucleus is present, and the enticing electrostatic force becomes weaker and the intensity of the electrons will be increases. Therefore, the lone pair occupies more space than the pair of bonds.

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Newton did not discover gravity, for early humans discovered that whenever they fell. what newton did discover is that gravity _

galben [10]

What Newton discovered is that gravity extends throughout the universe.

<h3>What is gravity?</h3>

The term gravity refers to the force that acts on a body in the universe. It is gravity that makes an object to fall when it is thrown up. The force of gravity acts on every object in the universe and it extends through the universe.

Humans have always known about gravity when they fall from a height and when they threw things up. However, human did not know that gravity extends throughout the universe.

Thus, what Newton discovered is that gravity extends throughout the universe.

Learn more about gravity:brainly.com/question/4014727

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1 year ago

A boat is travelling due west at a speed of 47 miles per hour. If the boat started off 170 miles directly north of the city of S

ankoles [38]

Answer is miles sir your welcome it was simple

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3 years ago

Government as an academic field of study

Savatey [412]

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2 years ago

Read 2 more answers

A bird flies 10 miles south, turns and flies 15 miles east. What distance did it fly.

vfiekz [6]

Answer:

wouldn't it be 25 miles?? yeah

Explanation:

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2 years ago

In an electric field, 0.90 joule of work is required to bring 0.45 coulomb of charge from point a to point

jarptica [38.1K]

The difference in electric potential energy between the two points is
$\Delta U = q \Delta V$
where q is the magnitude of the charge and $\Delta V$ is the electric potential difference.

But for energy conservation, the difference in electric potential energy $\Delta U$ between the two points is equal to the work done to move the charge between A and B:
$W=\Delta U$
so we have
$W=q \Delta V$

and by substituting the numbers of the problem, we find the value of $\Delta V$ :
$\Delta V = \frac{W}{q}= \frac{0.90 J}{0.45 C}=2 V$

3 0

2 years ago