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xeze [42]
3 years ago
13

A mosquito flies toward you with a velocity of 2.4 km/h [E]. If a distance of 35.0 m separates you and the mosquito initially, a

t what point (distance and time) will the mosquito hit your sunglasses if you are travelling toward the mosquito with a speed of 2.0 m/s and the mosquito is travelling in a straight path?
Physics
1 answer:
tangare [24]3 years ago
7 0

First convert the speed of mosquito to m/s:

So the mosquito is flying at (2,400/3,600) m/s, or ⅔ m/s. 

<span>

Since you are moving at 2m/s, so this makes the closing velocity between you and the mosquito to be 2⅔ m/s. </span>

Therefore the mosquito will hit your sunglasses at:<span>

35 m / (2⅔ m/s) = 13⅛ seconds. 

2.0 m/s * 13⅛ s = 26¼ m from your initial position. 

<span>⅔ m/s * 13⅛ s = 8¾ m from the mosquito's initial position. </span></span>
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A petrol tanker ha 2800kg when empty and hold 30m3 0f petrol when full. The denity of petrol i 740kg/m3. Calculate the ma of the
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The mass of the tanker with petrol is 250000 N.

We are given that,

Mass of tanker= m =2800 kg

Volume of petrol= v =30 m³

Density of petrol= d =740 kg/m³

Thus , mass , density and volume relation can be given as,

density= mass/ Volume

Mass = Density × Volume

Mass = 740× 30

Mass = 22200 kg

The mass of the petrol is 22200 kg.

Total mass of tanker with petrol = Mass of petrol + Mass of tanker

Total mass of tanker with petrol= 22200+ 2800 kg

Total mass of tanker with petrol= 25000 kg

Total weight of the tanker with petrol = Mass of tanker full of petrol× g

Where, weight = m × g ,(g =10m/s²)

Total weight of the tanker with petrol= 25000×10 = 250000 N

Therefore, the mass of petrol, total mass of tanker with petrol and weight of tanker with petrol would be  22200 kg, 25000 kg and 250000 N.

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4 0
1 year ago
The temperature at one of the Viking sites on Mars was found to vary daily from -90.OF to -5.0 C. Convert these temperatures to
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Answer:

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3 years ago
Can someone help? Please?
zubka84 [21]

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The temperature of the liquid in a container decreases as the liquid evaporates. Use kinetic theory to explain why.
melisa1 [442]

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3 years ago
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
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The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

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And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

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