Positive charge you gave the lines pointing away, negative charge is pointing toward. Don’t have a photo so I can’t fill in the blanks BUT I can tell you the logic
Answer:
M=125 kg
v=1.75 m/s
Explanation:
From the law of linear momentum
P =mv
Case 1 50*V =M* 0.7 equation 1
50*V =(M+50)* 0.5 equation 2
equating 1 and 2
M* 0.7=(m+50)* 0.5
0.2 M= 25
M=125 kg
Putting value of M in equation 1
50*V =125*0.7
V=1.75 m/s
Answer:
The minimum distance in which the car will stop is
x=167.38m
Explanation:
![39.7\frac{mi}{h}*\frac{1km}{0.621371mi}*\frac{1000m}{1km}*\frac{1h}{3600s}=17.747\frac{m}{s}](https://tex.z-dn.net/?f=39.7%5Cfrac%7Bmi%7D%7Bh%7D%2A%5Cfrac%7B1km%7D%7B0.621371mi%7D%2A%5Cfrac%7B1000m%7D%7B1km%7D%2A%5Cfrac%7B1h%7D%7B3600s%7D%3D17.747%5Cfrac%7Bm%7D%7Bs%7D)
∑F=m*a
∑F=u*m*g
The force of friction is the same value but in different direction of the force moving the car so it can stop so
![F=m*a\\a=\frac{F}{m}\\a=\frac{u*m*g}{m}\\a=u*g\\a=0.096*-9.8\frac{m}{s^{2} }](https://tex.z-dn.net/?f=F%3Dm%2Aa%5C%5Ca%3D%5Cfrac%7BF%7D%7Bm%7D%5C%5Ca%3D%5Cfrac%7Bu%2Am%2Ag%7D%7Bm%7D%5C%5Ca%3Du%2Ag%5C%5Ca%3D0.096%2A-9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
![a=-0.9408 \frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%3D-0.9408%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
![v_{f}^{2}=v_{o}^{2}+2*a*(x_{f}-x_{o})\\v_{f}=0 \\x_{o}=0\\0=v_{o}^{2}+2*a*x_{f}\\x_{f}=\frac{v_{o}^{2}}{2*a} \\x_{f}=\frac{(-17.747\frac{m}{s})^{2}}{2*(-0.9408)} \\x_{f}=167.38m](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3Dv_%7Bo%7D%5E%7B2%7D%2B2%2Aa%2A%28x_%7Bf%7D-x_%7Bo%7D%29%5C%5Cv_%7Bf%7D%3D0%20%5C%5Cx_%7Bo%7D%3D0%5C%5C0%3Dv_%7Bo%7D%5E%7B2%7D%2B2%2Aa%2Ax_%7Bf%7D%5C%5Cx_%7Bf%7D%3D%5Cfrac%7Bv_%7Bo%7D%5E%7B2%7D%7D%7B2%2Aa%7D%20%5C%5Cx_%7Bf%7D%3D%5Cfrac%7B%28-17.747%5Cfrac%7Bm%7D%7Bs%7D%29%5E%7B2%7D%7D%7B2%2A%28-0.9408%29%7D%20%5C%5Cx_%7Bf%7D%3D167.38m)