A light train made up of two cars is traveling at 100 km/h when the brakes are applied to both cars. Knowing that car A has a ma
ss of 35 Mg and car B a mass of 20 Mg, and that the braking force is 35 kN on each car, determine (a) the distance traveled by the train before it comes to a stop, (b) the force in the coupling between the cars while the train is showing down.
1 answer:
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a) Sketches of all possible pv-diagrams for the cycle are attached below
b) The work W for the process Ca is : 2462.8 J
<u>Given data :</u>
Amount of heat flowing out = 800 J
Ta = 200 K
Tb = 300 K
R = 800
<u>B) Determine the </u><u>work W </u><u>for the process</u><u> Ca</u><u> </u>
Wₐs = -pdv
= - [ pVb - pVa ] ---- ( 1 )
note : pVb = nRTb , pVa = nRTa
Equation ( 1 ) becomes
= -nR [ Tb - Ta ]
= - 2(8.314 ) [ 300 - 200 ]
= - 1662.87
given that W = 0 which is isochonic
dv = 0 ( cyclic process ) = d∅ - dw
∴ 0 = 800 - ( Wₐs + W )
Therefore : W = 800 + 1662.8 = 2462.8 J
Hence we can conclude that the work W for the process Ca = 2462.8 J
Learn more about Pv diagrams : brainly.com/question/25401637