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AleksandrR [38]
2 years ago
14

Joel reflected point P over the y-axis to get P'(–1, 5). Find the original coordinates of P.

Mathematics
1 answer:
Kay [80]2 years ago
6 0

Answer:

The original point P is (-1, -5)

Since the original point was reflected over the y axis then you would reflect over the x axis to get the original point and when you reflect over the x axis the x coordinates stay the same and you change the y coordinates to the opposite of what it is

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3 years ago
Solve for b .<br><br> + b = -1<br> b =
Alik [6]

Answer:

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Step-by-step explanation:

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+ b = - 1 and this is the same as b = - 1.

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7 0
3 years ago
At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
Gennadij [26K]

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<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

Then to obtain the slope of the curve we have; y = 19 - 2x

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Hence;

y = 1/4 - 5(-1/2)

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Thus the points are; (7/2, -1/2)

Learn more about normal curve:brainly.com/question/10664419

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7 0
1 year ago
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