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Anastaziya [24]
3 years ago
8

A 13.3 kg box sliding across the ground

Physics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

<em>0.25</em>

Explanation:

According to newtons law of motion

\sum F_x = ma

F_f =  ma

nR = ma

nmg = ma

ng = a

n = a/g

g is the acceleration due to gravity

Given

a = 2.42m/s²

g = 9.8m/s²

Substitute into the formula;

n = 2.42/9.8

n = 0.25

<em>Hence the coefficient of kinetic friction is 0.25</em>

<em></em>

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3 years ago
If the volume is held constant, what happens to the pressure of a gas as temperature is decreased? Explain.
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Explanation:

Given

Volume is held constant that is it is a isochoric process.

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\frac{P_1}{P_2}=\frac{T_1}{T_2}

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6 0
3 years ago
Compare the force of air resistance and the force of gravity on an object falling at its terminal velocity.
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7 0
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A man weighs himself twice in an elevator. When the elevator is at rest, he weighs 824 N; when the elevator starts moving upward
kifflom [539]

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When he is at rest, is weight can be calculated as:

W = g*m

where:

m = mass of the man

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We know that at rest his weight is W = 824N, then we have:

824N = m*9.8m/s^2

824N/(9.8m/s^2) = m = 84.1 kg

Now, when the elevators moves up with an acceleration a, the acceleration that the man inside fells down is g + a.

Then the new weight is calculated as:

W = m*(g + a)

and we know that in this case:

W = 932N

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m = 84.1 kg

Then we can find the value of a if we solve:

932N = 84.1kg*(9.8m/s^2 + a)

932N/84.1kg = 11.1 m/s^2 = 9.8m/s^2 + a

11.1 m/s^2 - 9.8m/s^2 = a = 1.3 m/s^2

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