Answer / Explanation
It is worthy to note that the question is incomplete. There is a part of the question that gave us the vale of V₀.
So for proper understanding, the two parts of the question will be highlighted.
A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s later. You may ignore air resistance.
a) What must the height of the building be for both balls to reach the ground at the same time if (i) V₀ is 6.0 m/s and (ii) V₀ is 9.5 m/s?
b) If Vo is greater than some value Vmax, a value of h does not exist that allows both balls to hit the ground at the same time.
Solve for Vmax
Step Process
a) Where h = 1/2g [ (1/2g - V₀)² ] / [(g - V₀)²]
Where V₀ = 6m/s,
We have,
h = 4.9 [ ( 4.9 - 6)²] / [( 9.8 - 6)²]
= 0.411 m
Where V₀ = 9.5m/s
We have,
h = 4.9 [ ( 4.9 - 9.5)²] / [( 9.8 - 9.5)²]
= 1152 m
b) From the expression above, we got to realise that h is a function of V₀, therefore, the denominator can not be zero.
Consequentially, as V₀ approaches 9.8m/s, h approaches infinity.
Therefore Vₙ = V₀max = 9.8 m/s
Answer:
I think d is the answer haha
Answer:
The acceleration of the player is - 4.9 m/s²
Explanation:
The given is:
1. The mass of the player is 55 kg
2. His initial speed is 4.6 m/s
3. The coefficient of the kinetic fraction between the player and the
ground is 0.50
We need to find the player acceleration
According to Newton's Law
→ ∑ forces in direction of motion = mass × acceleration
There is only the friction force opposite to the motion
→ Friction force = μR
where μ is the coefficient of friction and R is the normal reaction
→ The normal reaction R = mg
where m is the mass and g is the acceleration of gravity
→ m = 55 kg , g = 9.8 m/s²
→ R = 55 × 9.8 = 539 N
→ ∑ F = - μR
→ - μR = m × a
→ μ = 0.5 , R = 539 N , m = 55
→ -(0.5)(539) = 55 × a
→ - 269.5 = 55 a
Divide both sides by 55
→ a = - 4.9 m/s²
The acceleration of the player is - 4.9 m/s²
Learn more:
You can learn more about Newton's law in brainly.com/question/11911194
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Answer:
Option 2. and 3.
Explanation:
Anode heel effect or simply heel effect is observed in X-ray tubes.
It is the change in the intensity of the emitted X-rays from the anode and this intensity is direction dependent and depends on the direction of the emitted X-rays along the axis of anode-cathode.
This effect results from the absorption of X-rays prior to leaving the anode, their production source.
The absorption of photons is more in the anode heel than the toe of the anode which results in the anode heel effect.
Answer:
The magnitude of the acceleration of the box is 2 m/s².
Explanation:
Given:
Mass of the box, 
kg
Force acting towards east, 
N
Frictional force acting towards west, 
N
Let the acceleration be 
m/s².
Now, net force acting on the box towards east is given as:
From Newton's second law of motion,
Therefore, the magnitude of the acceleration of the box is 2 m/s².
