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Digiron [165]
3 years ago
10

What is the domain of this function?

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Given:

Consider the below figure attached with this question.

To find:

The domain of the graphed function.

Solution:

Domain is the set of input values or x-values.

From the given graph it is clear that the function has one end point at (0,9) and an arrow at (8,1). It means it is not a line because it is a ray that moves further from point (8,1) in the downward direction.

The minimum value of x is 0 and their is no maximum value of x because  graph of the function is a ray. So, the domain of the given function is:

\text{Domain}=\{x|x\geq 0\}

Therefore, the correct option is A.

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Please help ASAP this is timed
antiseptic1488 [7]

Answer:

1.)616 in

2.)260 ft

3.) 744 mm

Step-by-step explanation:

5 0
3 years ago
in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation o
Alinara [238K]

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

z = \dfrac{x - \mu }{\sigma}

z = \dfrac{x - 170000 }{16500}

Now;

P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})

P( Z < \dfrac{T- 170000}{16500})< 0.02

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

\dfrac{T- 170000}{16500}

{T- 170000}

{T- 170000}< - 33990

{T}< - 33990+ 170000

{T}

Thus; the guarantee period should be less than 136010 miles

4 0
4 years ago
Given that p²,q² are two roots of x²-x+16=0. <br>Form another equation with roots 1/p,1/q.
statuscvo [17]

Answer:

  x² -3/4x +1/4 = 0

Step-by-step explanation:

Consider the two equations in factored and expanded forms:

  (x -p²)(x -q²) = x² -(p²+q²)x +p²q² = 0   ⇒   p²+q² = 1, p²q² = 16

and

  (x -1/p)(x -1/q) = x² -(1/p+1/q)x +1/(pq) = 0

Consider the squares of the sum and product of roots:

  constant term: (1/(pq))² = 1/(p²q²) = 1/16   ⇒   1/(pq) = √(1/16) = 1/4

  x-term: (1/p +1/q)² = (p +q)²/(pq)² = (p² +q² +2pq)/(p²q²)

  = (p² +q²)/(p²q²) +2/(pq)

  = 1/16 +2/√16 = 9/16   ⇒   (1/p +1/q) = √(9/16) = 3/4

Then the equation with roots 1/p and 1/q is ...

  x² -3/4x +1/4 = 0

6 0
3 years ago
tyler wants to use $300 he has saved to buy a new guitar and join a music club. the guitar costs $140. the music club has a $25
tresset_1 [31]
So first tyler has to purchase his guitar. 300-140=160. he has 160 dollars to spend on the music club. Tyler can afford the membership for 13 months and he will have $4.65 left
4 0
4 years ago
A ball is dropped from a height of 30 feet and each time it hits the ground it bounces 0.75 of the previous height. What is the
QveST [7]
If the ball is "starting" at 30 feet, then to get how high it went the bounce, we simply multiply 0.75 times 30, and to get the next bounce's height, is again (30*0.75)0.75, and so on.

so... the 0.75 or 3/4 is our "multiplier" to get the next term's value, or our "common ratio".  So is just a geometric sequence, if the first term is 30, the common ratio is 0.75, what's the 4th term?  Because the first bounce happens after the 30 feet, at the 2nd term, thus the 4th term is the 3rd bounce.

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=30\\&#10;r=0.75\\&#10;n=4&#10;\end{cases}&#10;\\\\\\&#10;a_4=30\cdot (0.75)^{4-1}\implies a_4=30(0.75)^3


4 0
3 years ago
Read 2 more answers
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