Answer:
1.)616 in
2.)260 ft
3.) 744 mm
Step-by-step explanation:
Answer:
the guarantee period should be less than 136010 miles
Step-by-step explanation:
From the given information;
Let consider Y to be the life of a car engine
with a mean μ = 170000
and a standard deviation σ = 16500
The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.
i.e
P(Y < T ) < 0.02
For the variable of z ; we have:


Now;


From Z table ;
At P(Z < -2.06) ≅ 0.0197 which is close to 0.02





Thus; the guarantee period should be less than 136010 miles
Answer:
x² -3/4x +1/4 = 0
Step-by-step explanation:
Consider the two equations in factored and expanded forms:
(x -p²)(x -q²) = x² -(p²+q²)x +p²q² = 0 ⇒ p²+q² = 1, p²q² = 16
and
(x -1/p)(x -1/q) = x² -(1/p+1/q)x +1/(pq) = 0
Consider the squares of the sum and product of roots:
constant term: (1/(pq))² = 1/(p²q²) = 1/16 ⇒ 1/(pq) = √(1/16) = 1/4
x-term: (1/p +1/q)² = (p +q)²/(pq)² = (p² +q² +2pq)/(p²q²)
= (p² +q²)/(p²q²) +2/(pq)
= 1/16 +2/√16 = 9/16 ⇒ (1/p +1/q) = √(9/16) = 3/4
Then the equation with roots 1/p and 1/q is ...
x² -3/4x +1/4 = 0
So first tyler has to purchase his guitar. 300-140=160. he has 160 dollars to spend on the music club. Tyler can afford the membership for 13 months and he will have $4.65 left
If the ball is "starting" at 30 feet, then to get how high it went the bounce, we simply multiply 0.75 times 30, and to get the next bounce's height, is again (30*0.75)0.75, and so on.
so... the 0.75 or 3/4 is our "multiplier" to get the next term's value, or our "common ratio". So is just a geometric sequence, if the first term is 30, the common ratio is 0.75, what's the 4th term? Because the first bounce happens after the 30 feet, at the 2nd term, thus the 4th term is the 3rd bounce.