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Digiron [165]
3 years ago
10

What is the domain of this function?

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Given:

Consider the below figure attached with this question.

To find:

The domain of the graphed function.

Solution:

Domain is the set of input values or x-values.

From the given graph it is clear that the function has one end point at (0,9) and an arrow at (8,1). It means it is not a line because it is a ray that moves further from point (8,1) in the downward direction.

The minimum value of x is 0 and their is no maximum value of x because  graph of the function is a ray. So, the domain of the given function is:

\text{Domain}=\{x|x\geq 0\}

Therefore, the correct option is A.

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Please help!!!! I dont get it! I need this question correct!!!!
Marianna [84]
That is a trapezoid.
Trapezoid Area = (Sum of the Bases / 2) * height
Trapezoid Area = ((2/5 + 1 and 1/5) / 2) * 1 (2/3)
Trapezoid Area = ((8 / 5)/2) * 5 / 3
Trapezoid Area = 4 / 5 * 5 / 3
Trapezoid Area = 20 / 15 mm = 4 / 3 mm





8 0
4 years ago
HELP ASAP PLEASEEEE!
Llana [10]

Answer:

it is c

Step-by-step explanation:

4 0
3 years ago
43 ones times 3 tens = how many tens
romanna [79]
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3 0
3 years ago
Read 2 more answers
Justify why a / b x b / c x c /d x d / e is equal to a /e when B C D and E are not zero
Maru [420]

a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

 

PROVE

 a/b * b/c * c/d * d/e

= (a/b *b/c) * (c/d * d/e)

= ab/bc * (c/d * d/e)

= a/c * (c/d * d/e)

= a/c * (cd/de)

= a/c * c/e

= ac/ce

= a/e

 

Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

7 0
4 years ago
Find the area of the kite. The figure is not drawn to scale.
aleksandrvk [35]

Answer:

The area of the kite is 42\ units^{2}

Step-by-step explanation:

we know that

The area of a kite is half the product of the diagonals

so

A=\frac{1}{2}(D1*D2)

we have

D1=2*(3)=6\ units

<em>Find the length side of diagonal D2</em>

Applying the Pythagoras Theorem

D2=\sqrt{5^{2}-3^{2}} +10\\ \\D2=4+10\\ \\D2=14\ units

<em>Find the area of the kite</em>

we have

D1=6\ units

D2=14\ units

substitute

A=\frac{1}{2}(D1*D2)

A=\frac{1}{2}(6*14)=42\ units^{2}

3 0
3 years ago
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