Answer: 10
Explanation:
The detailed solution is contained in the image attached. The molar mass of hydrated and anhydrous salts are obtained and the number of moles of hydrated and hydrated salts are equated. The masses of hydrated and anhydrous salts are gives in the question and are simply substituted accordingly. This can now be used to obtain the number of molecules of water of crystallization as required in the question.
K2SO4 MgSO4 Al2(SO4)3 Ge2(SO4)4
KNO3 Mg(NO3)2 Al(NO3)3 Ge(NO3)4
KCH3COO Mg(CH3COO)2 Al(CH3COO)3 Ge(CH3COO)4
Note: all of the numerical are subscript to each element or compound.
One can tell by looking at the titration curve of an acid and base whether the acid used is a strong acid or a weak acid. For a titration of a strong acid and a strong base, the pH at the equivalence point will be neutral, that is, pH 7. If the titration involves a weak acid and a strong base, the pH at the equivalence point will not be neutral, the solution will be basic at the equivalence point.
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