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2 years ago

(08.02 LC)

Chemistry

2 answers:

Varvara68 [4.7K]2 years ago

7 0

Answer:

The correct answer is a both are ratios of amount of solute over the amount of solution.

Explanation:

Molarity of a substance can be defined as the gram equivalent weight of that substance is dissolved in 1000 ml or 1 litre of water.

For example 1(N) NaOH means 40gm NaOH is being dissolved in 1 litre of water

Percent by mass can be defined as how many percent of that substance is dissolved in 100 ml of water.

For example 20% NaOH solution means 20gm NaOH is being dissolved in 100ml of water.

Solnce55 [7]2 years ago

5 0

Answer: They are different units of concentration

Explanation:

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Read 2 more answers

Cyclobutane, C4H8, consisting of molecules in which four carbon atoms form a ring, decomposes, when heated, to give ethylene. Th

frosja888 [35]

Answer:

The concentration of cyclobutane after 875 seconds is approximately 0.000961 M

Explanation:

The initial concentration of cyclobutane, C₄H₈, [A₀] = 0.00150 M

The final concentration of cyclobutane, [ $A_t$ ] = 0.00119 M

The time for the reaction, t = 455 seconds

Therefore, the Rate Law for the first order reaction is presented as follows;

$\text{ ln} \dfrac {[A_t]}{[A_0]} = \text {-k} \cdot t }$

Therefore, we get;

$k = \dfrac{\text{ ln} \dfrac {[A_t]}{[A_0]}} {-t }$

Which gives;

$k = \dfrac{\text{ ln} \dfrac {0.00119}{0.00150}} {-455} \approx 5.088 \times 10^{-4}$

k ≈ 5.088 × 10⁻⁴ s⁻¹

The concentration after 875 seconds is given as follows;

[ $A_t$ ] = [A₀]· $e^{-k \cdot t}$

Therefore;

[ $A_t$ ] = 0.00150 × $e^{5.088 \times 10^{-4} \times 875}$ = 0.000961

The concentration of cyclobutane after 875 seconds, [ $A_t$ ] ≈ 0.000961 M

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2 years ago