The answer would be KMnO4, please let me know if you would like me to explain how i got this
Answer:
im sorry, but im not sure
Explanation:
Answer:
Hey there!
22.0 has three significant figures.
Let me know if this helps :)
The question is incomplete, here is the complete question:
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1 M⁻¹s⁻¹
![2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)](https://tex.z-dn.net/?f=2SO_3%28g%29%5Crightarrow%202SO_2%28g%29%2BO_2%28g%29)
Suppose a vessel contains SO₃ at a concentration of 1.44 M. Calculate the concentration of SO₃ in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.
<u>Answer:</u> The concentration of
in the vessel after 0.240 seconds is 0.24 M
<u>Explanation:</u>
For the given chemical equation:
![2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)](https://tex.z-dn.net/?f=2SO_3%28g%29%5Crightarrow%202SO_2%28g%29%2BO_2%28g%29)
The integrated rate law equation for second order reaction follows:
![k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_o%7D%5Cright%29)
where,
k = rate constant = ![14.1M^{-1}s^{-1}](https://tex.z-dn.net/?f=14.1M%5E%7B-1%7Ds%5E%7B-1%7D)
t = time taken= 0.240 second
[A] = concentration of substance after time 't' = ?
= Initial concentration = 1.44 M
Putting values in above equation, we get:
![14.1=\frac{1}{0.240}\left (\frac{1}{[A]}-\frac{1}{1.44}\right)](https://tex.z-dn.net/?f=14.1%3D%5Cfrac%7B1%7D%7B0.240%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B1.44%7D%5Cright%29)
![[A]=0.245M](https://tex.z-dn.net/?f=%5BA%5D%3D0.245M)
Hence, the concentration of
in the vessel after 0.240 seconds is 0.24 M