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docker41 [41]
3 years ago
12

Use the following steps to balance the redox reaction below:

Chemistry
1 answer:
wel3 years ago
6 0

Answer:

(a)

Oxidation

Na -> Na+  +  e

Reduction

Cu2+   + 2e -> Cu

(b) Just multiply oxidation half-reaction by 2 and reduction half-reaction by 1.

2Na -> 2Na+  + 2e

Cu2+  + 2e -> Cu

(c) 2Na + Cu2+ -> 2Na+  +  Cu (2e cancels each other)

Please be reminded, this answer may not be correct.

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BlackZzzverrR [31]

Answer: 3 & 4

Explanation:

8 0
3 years ago
What change causes a substance to change states of matter?
pochemuha
If the states of matter have changed such as from solid to liquid, you have to remove or add energy.
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3 years ago
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HELPPPP PLEASEEEE Metal or Non-metal?
Tcecarenko [31]

Answer:

Fluorine:non-metal

Bromine:non-metal

Hydrogen:non-metal

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8 0
3 years ago
A solution is prepared by dissolving 0.23 mol of lactic acid and 0.27 mol of sodium lactate in water sufficient to yield 1.00 L
PtichkaEL [24]

Explanation:

The solution of the lactic acd and sodium lactate is referred to as a buffer solution.

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. In this case, the weak acid is the lactic acid and the conjugate base is the sodium lactate.

Buffer solutions are generally known to resist change in pH values.

When a strong base (in this case, NaOH) is added to the buffer, the lactic acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base, so we have:

HA + OH- → A- + H2O.

Since the added OH- is consumed by this reaction, the pH will change only slightly.

The NaOH reacts with the weak acid present in the buffer sollution.

6 0
3 years ago
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Select the correct hybridization for the central atom based on the electron geometry cocl2 (carbon is the central atom).
Rainbow [258]
In this compound (Phosgene) the central atom (carbon is Sp² Hybridized).

Sp, Sp² and Sp³ can be calculated very simply by doing three steps, 

Step 1:
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Step 2:
          Count lone pair of electron, each lone pair counts for s and p. In this case there is no lone pair of electron on carbon, so not included.

Step 3:
          Count single bonds for s and p. As we have already assigned s to the double bond, now one p for one single bond, and other p for the other single bond.

Result:
          So, we counted 1 s for double bond, 1 p for one single and other p for second single bond. As a whole we got,

                                                       Sp²

Practice:
You can practice for hybridization of Oxygen in this molecule. Oxygen has 2 lone pair of electrons. (Hint: Sp² Hybridization)
7 0
3 years ago
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