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pantera1 [17]
2 years ago
12

Lead (11) oxide dissolves in both

Chemistry
1 answer:
inn [45]2 years ago
7 0

Answer:

bacic

Explanation:

it is very soluble in water

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Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so
kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For NaOH :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{90.0\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 2.2502\ mol

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

<u>Final concentration of NaOH = 0.75 M</u>

5 0
3 years ago
An alloy is made up of more than one type of what?
pychu [463]
More than one type of metallic elements.
4 0
3 years ago
Calculate the mass in grams of 1.13 x 102 molecules of propane. The chemical formula for propane is C3H8.
g100num [7]
Moles = (6.74*10^23)/(6.02*10^23) =1.119 moles

1.119*44.09=49.36g
3 0
3 years ago
If 5.0 kJ of energy is added to a 15.5-g sample of water at 10.°C, the water is Group of answer choices
BaLLatris [955]

Answer:

The water is completely vaporized at this stage.

Explanation:

The complete question is

If 5.0 kJ of energy is added to a 15.5-g sample of water at 10.°C, the water is

-boiling

-completely vaporized

-frozen solid

-decomposed

-still a liquid

Energy added = 50 kJ = 50000 J

mass of water = 15.5 g = 0.0155 kg

temperature of water = 10 °C

We know that the energy posses by a mass of water at a given temperature is given as

H = mcT

where H is the energy possessed by the mass of water

m is the mass of the water

c is the specific heat capacity of water = 4200 J/ kg- °C

T is the temperature of the water

substituting values, the energy of this amount of water is

H = 0.0155 x 4200 x 10 = 651 J

If 50 kJ is added to the water, the energy increases to

50000 J + 651 J = 50651 J

Temperature of this water at this stage will be gotten from

H = mcT

we solve for the new temperature

50651 = 0.0155 x 4200 x T

50651 = 65.1 x T

T = 50651/65.1 = 778.05 °C

This temperature is well over 100 °C, which is the vaporization temperature of water, but less than 3000 °C for its molecules to decompose.

3 0
3 years ago
Which statement best descibes what happens when a person sees a orange t-shirt?
tangare [24]
B. light reflects off of the t shirt and enters the human eye
6 0
3 years ago
Read 2 more answers
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