Answer:
24 atm is the total pressure exerted by the gases
Explanation:
We propose this situation:
In a vessel, we have 4 gases (for example, hydrogen, Xe, methane and chlorine)
Each of the gases has the same pressure:
6 atm → hydrogen
6 atm → xenon
6 atm → methane
6 atm → chlorine
To determine the total pressure, we sum all of them:
Partial pressure H₂ + Partial pressure Xe + Partial pressure CH₄ + Partial pressure Cl₂ = Total P
6 atm + 6 atm + 6 atm + 6 atm = 24atm
Answer:
v = 10 km/h
Explanation:
Step 1: Given data
- Distance traveled in the Bike Trip (d): 1 km
- Time elapsed in the Bike Trip (t): 0.1 h
Step 2: Calculate the speed in the Bike Trip
The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.
v = d/t
v = 1 km/0.1 h
v = 10 km/h
The speed is 10 kilometers per hour.
Answer:
This question is incomplete, however, the unknown compound can be inferred to be "Lithium Bromide"
Explanation:
The unknown compound firstly is said to be an ionic compound. An ionic/electrovalent compound is a compound in which it's constituent ions transfer/receive electron(s). They are mostly made of group 1 and group 7 elements. Examples include NaCl, NaF, LiF and KCl.
Also, the ion (metallic ion) that produces a red flame test colour in a flame test is the <u>Lithium ion (Li⁺).</u> Also, when dissolved in water or hexane, the only halogen that produces a red/orange colour is bromine. Hence, the unknown ionic compound can be inferred to be Lithium Bromide.
Answer:
Volume of the sulfuric acid (25cm³), same mass of each metal (1g)
Explanation:
In an experiment, the CONTROL VARIABLE also known as constant is the variable that is kept unchanged for all groups in an experiment. This is done in order not to influence the outcome of the experiment.
In this case, students are trying to investigate the reactivity of four different metals. They added 1 g of each metal to 25cm³ of sulfuric acid and recorded the temperature change. Based on the explanation of control variable above, the VOLUME OF SULFURIC ACID (25cm³) and the MASS OF EACH METAL (1g) are the CONTROL VARIABLES because they are the same or unchanged in this experiment.
<span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles
Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq)
Ksp = (Sr++)^3(As04^-3)^2
(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4
(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4
<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th
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