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3 years ago

A pendulum is in a spacecraft to measure

Physics

1 answer:

Tcecarenko [31]3 years ago

4 0

Answer:

For small angles (✓ < 30 degrees), the period of a simple pendulum4can be approximated by: 3A radian is an angle measure based upon the circumference of a circle C =2⇡r where r is the radius of the circle. A complete circle (360 ) is said to have 2⇡ radians. Therefore, a 1/4 circle (90 )is⇡/2 radians.

Explanation:

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An experimenter using a gas thermometer found the pressure at the triple point of water (0.01°C) to be 4.80 × 10⁴ Pa and the pre

irakobra [83]

Answer:

$T = -282.33^o C$

Explanation:

As we know that the relation between temperature and pressure is a linear relation

so we have

$P - P_o = \frac{P_1 - P_o}{T_1 - T_o} (T - T_o)$

here we know that

$P_1 = 6.50 \times 10^4$

$P_o = 4.80 \times 10^4$

$T_1 = 100^o C$

$T_o = 0.01^o C$

now we will have

$P - 4.80 \times 10^4 = \frac{(6.50 - 4.80)\times 10^4}{100 - 0.01}(T - 0.01)$

$P = 4.80 \times 10^4 + 170.02(T - 0.01)$

now if P = 0

then we will have

$0 = 4.80 \times 10^4 + 170.02(T - 0.01)$

$T = -282.33^o C$

7 0

3 years ago

How can we measure magnitude of displacement from a v-t curve?

Ratling [72]

Answer:

The displacement can be calculated by measuring the area of the curve when we move along the t curve. So, that would give the displacement.

Explanation:

4 0

3 years ago

A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire that has a 3.83 ×

Tju [1.3M]

Answer:

Explanation:

power of a heating element = V² / R where V is voltage and R is resistance

putting in the values

5200 = 75² / R

R = 1.082 ohm

Formula for resistance

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

1.082 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 8.29 m

b )

power of a heating element = V² / R , R is new resistance

5200 = 120² / R

R = 2.77 ohm

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

2.77 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 21.22 m

4 0

3 years ago

If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface

Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile = $\frac{1}{2}mv_e^2-\frac{GMm}{R}$ ... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, $v_e=\sqrt{\frac{2GM}{R}}$

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

$\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h}$ ...(2)

(1)=(2)

⇒ $\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}$

⇒ $G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2$

⇒ $\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})$

⇒ $\frac{h}{R+h} = \frac{3}{4}$

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.

4 0

3 years ago

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the weigh of an unloaded mazda Cx-5 is appromimately 3300 pounds. what is the weight in units of newtons.

Lana71 [14]

14,697.13

Hope this Helps you :)

5 0

4 years ago

Read 2 more answers