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3 years ago

14

Which phenomena did Michael Faraday explore to help him invent the motor and the generator?

2 answers:

mamaluj [8]3 years ago

8 0

The best and most correct answer among the choices provided by the question is the fourth choice. The phenomenon that Michael Faraday explored was electricity and magnetism. I hope my answer has come to your help. God bless and have a nice day ahead!

dezoksy [38]3 years ago

3 0

Answer:

electricity and motion

Explanation:

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If a marathon runner averages 9.50 mi/h, how many minutes does it take him or her to run a 26.22-mi marathon?

horsena [70]

Answer: 196 minutes

Explanation: 26.22/9.50 = 2.76

2 hours and 76 minutes equals 196 minutes

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3 years ago

Why are there two types of core?

dlinn [17]

Answer:

because the dog cat moster ate a bean. the answer is 68

Explanation:

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3 years ago

The total resistance of a parallel circuit is 25 ohms. If the total current is 100mA, how much current is through a 220 ohm resi

gulaghasi [49]

Answer:

The current across the resistance is 0.011 A.

Explanation:

Total resistance, R = 25 ohms

Total current, I = 100 mA = 0.1 A

Let the voltage is V.

By the Ohm's law

V = I R

V = 0.1 x 25 = 2.5 V

Now the resistance is R' = 220 ohm

As they are in parallel so the voltage is same. Let the current is I'.

V = I' x R'

2.5 = I' x 220

I' = 0.011 A

7 0

2 years ago

A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.90 x 105 P

worty [1.4K]

Answer:

The magnitude of the force is 34.59 N.

Explanation:

Given that,

Inside pressure $P_{in}= 1.90\times10^{5}\ Pa$

Area $A=3.90\times10^{-4}\ m^2$

Outside pressure = 1 atm

We need to calculate the magnitude of the force

Using formula of force

$F_{net}=F_{in}-F_{out}$

$F_{net}=(P_{in}-P_{out})A$

Where, $P_{in}$ =inside Pressure

$P_{out}$ =outside Pressure

A = area

Put the value into the formula

$F_{net}=(1.90\times10^{5}-1.013\times10^{5})3.90\times10^{-4}$

$F_{net}=34.59\ N$

Hence, The magnitude of the force is 34.59 N.

6 0

3 years ago

A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collis

Elza [17]

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2 ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1 ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

4 0

2 years ago