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Sliva [168]
3 years ago
8

DawdDAWdADdwaadadadawddawd

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

yyuuuyytt

Explanation:

ggyhggggg,,,,,,,76yyygtyyhgyyggyuhu ubbububuuh7h7h

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The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P
expeople1 [14]

Answer : The ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

Solution :  Given,

K_p=1.5\times 10^6

p_{O_2} = 0.21 atm

The given equilibrium reaction is,

NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)

The expression of K_p will be,

K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}

Now put all the given values in this expression, we get:

1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}

\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}

\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5

Therefore, the ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

5 0
3 years ago
Would fluorine form a positive or a negative ion?
IceJOKER [234]
It would form a negative ion... it lacks 1 e in its valence shell., it is easier for F to accept an e than to shed all existing 7.
e= electron
8 0
3 years ago
What is the process by which sand dunes occur?
Arte-miy333 [17]
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3 0
3 years ago
0.00000000082 -<br> scientific notation
Nadusha1986 [10]

Answer:

8.2 x 106^-11

Explanation:

To begin this problem you must remember the basic rule of scientific notation, which is, must be between 1-10. .000000000082 is much smaller than 1. However by moving the decimal 11 spots to the right, we can make it 8.2

Continue to move the decimal to the right until the value is in the 1-10 range. Make sure to count the moves to the right.

Once the decimal is in the right spot count the spots moved.

Since the number is wayyy smaller than the answer given the number will be negative 10^-11, in order to make it what is was before.

6 0
3 years ago
Which molecule has a high specific heat?<br><br> a) C2H6<br> b) C2H6O<br> c) H2O
dem82 [27]
H2O is the correct answer :)
4 0
2 years ago
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