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denpristay [2]
3 years ago
10

In a certain acidic solution at 25 ∘C, [H+] is 100 times greater than [OH −]. What is the value for [OH −] for the solution?

Chemistry
1 answer:
solong [7]3 years ago
3 0

<u>Answer:</u> The value of [OH^-] for the solution is 10^{-6}M

<u>Explanation:</u>

To calculate the concentration of hydroxide ion for the solution, we use the equation:

[H^+]\times [OH^-]=10^{-14}

We are given:

[H^+]=100\times [OH^-]

Putting values in above equation, we get:

100\times [OH^-]\times [OH^-]=10^{-14}

[OH^-]^2=\frac{10^{-14}}{100}

[OH^-]=\sqrt{10^{-12}}

[OH^-]=10^{-6}M

Hence, the value of [OH^-] for the solution is 10^{-6}M

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Newly occupied volume is 7.672L by N2 gas.  

<u>Explanation:- </u>

Given  

V= 9.20 L, T(i) = T (f) = 294 K, P (i) = 0.959 atm, P (f) = 1.15 atm

To Find V (f)  

Solution

According to the gas equation  

PV= nRT

Where P=Pressure

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Also we know the relation between pressure, volume and temperature as

PV/T = constant

\frac{p(i) V(i) \times p(f) V(f)}{T(i) \times T(f)}

V(f)=[P(i) V(i) T(f)] \div[T(i) P(f)]

Where P(i)V(i)/T(i) are the initial values of Pressure, Volume and Temperature.

P(f)V(f)/T(f) are the final values of Pressure, Temperature and Volume.

Substitute the known values in the equation we get

= \frac{0.959 \times 9,2 \times 294}{294 \times 1.15}

=2574.94 \div 338.1

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Thus the final volume of the system is 7.672 L

5 0
3 years ago
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Jason combines the two intermediate steps shown.
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Answer:

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Explanation:

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2) 2NO(g )+ O₂(g) → 2NO₂(g).

  • Adding the two equation with cancelling the intermediate (NO), we get:

<em>N₂(g ) + 2O₂(g) → 2NO₂(g).</em>

<em></em>

NO is cancelled out because there is one in each equation in the products side in eq. 1 and in oriduct side in eq. 2.

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Answer:

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