The student originally has 252 grams of water in this experiment.
LAW OF CONSERVATION OF MASS:
- The law of conservation of mass explains that matter (mass) can neither be created nor destroyed but can be changed from one form to another.
- This means that in a chemical reaction, the sum of the masses of the reactants must equate to the total mass of product(s).
- According to this question, a student conducts an experiment to separate water into hydrogen and oxygen. The student collects 28.0 g of hydrogen and 224.0 g of oxygen.
- Since hydrogen and oxygen are the constituent elements of water, the sum of their masses must equate the mass of water.
- Therefore, 224g of oxygen + 28g of hydrogen = 252g of water.
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Answer:
V₂ = 495.89 mL
Explanation:
Given data:
Initial number of moles = 0.213 mol
Initial volume = 652 mL
Final number of moles = 0.162 mol
Final volume = ?
Solution:
V₁/n₁ = V₂/n₂
By putting values,
652 mL/0.213 mol = V₂ /0.162 mol
V₂ = 652 mL 0.162 mol /0.213 mol
V₂ = 105.62 mL.mol /0.213 mol
V₂ = 495.89 mL
<u>Molar mass of CO₂:
</u>
mC + 2×mO = 12g + 2×16g = 12g + 32g =<u> 44 g/mol</u>
