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notka56 [123]
3 years ago
15

A boy of mass 40kg eats bananas contains of 980 joule. If this energy is used to lift him up from ground,the height to which he

can climb is
Physics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

h = 2.49 [m]

Explanation:

In order to solve this problem we must use the definition of potential energy, which tells us that energy is equal to the product of mass by gravity by height.

The potential energy can be calculated by means of this equation:

Ep = m*g*h

where:

Ep = potential energy = 980 [J]

m = mass = 40 [kg]

g = gravity acceleration = 9.81 [m/s^2]

h = elevation [m]

Now replacing:

980 = 40*9.81*h

h = 2.49 [m]

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In the simulation, there are three balls on the floor. Drag each of them up off the floor, and then let go. See what happens to
Vlad1618 [11]

Answer:

I hope this helps and I'm not to late

A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.

Explanation:

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7 0
2 years ago
you have been called to testify as a as an expert witness in a trial involving a head-on collision Car A weighs 1515 pounds and
GrogVix [38]

Answer:

70.6 mph

Explanation:

Car A mass= 1515 lb

Car B mass=1125 lb  

Speed of car B is 46 miles/h

Distance before locking, d=19.5 ft

Coefficient of kinetic friction is 0.75

Initial momentum of car B=mv where m is mass and v is velocity in ft/s  

46 mph*1.46667=67.4666668 ft/s

Momentum_B=1125*67.4666668 ft/s

Initial momentum of car A is given by

Momentum_A=1515v_a where v_a is velocity of A

Taking East as positive and west as negative then the sum of initial momentum is

1515v_a-(1125*67.4666668 ft/s)

The common velocity is represented as v_c hence after collision, the final momentum is

Momentum_final=(m_a+m_b)v_c=(1515+1125)v_c=2640v_c

From the law of conservation of linear momentum, sum of initial and final momentum equals each other hence

1515v_a-(1125*67.4666668 ft/s)= 2640v_c

The acceleration of two cars a=-\mug=-0.75*32.17=-24.1275 ft/s^{2}

From kinematic equation

v^{2}=u^{2}+2as hence

v^{2}-u^{2}=2as

0^{2}-(v_c)^{2}=2*-24.1275*19.5

v_c=\sqrt{2*24.1275*19.5}=30.67 ft/s

Substituting the value of v_c in equation 1515v_a-(1125*67.4666668 ft/s)= 2640v_c

1515v_a-(1125*67.4666668 ft/s)= 2640*30.67

1515v_a=(1125*67.4666668 ft/s)+2640*30.67

v_a=\frac {156868.8}{1515}=103.5438 ft/s

\frac {103.5438}{1.46667}=70.59787 mph\approx 70.60 mph

3 0
3 years ago
A water pump is a positive displacement-type pump true or false
Kay [80]

Answer: True

A water pump belong to a positive displacement pump that provides constant flow of water at fixed speed, regardless of changes in the counter pressure. The two main types of positive displacement pump are rotary pumps and reciprocating pumps.

Moreover, water pump is a reciprocating positive displacement pump that have an expanding cavity on the suction side and a decreasing cavity on the discharge side. In water pumps, the liquid flows into the pumps as the cavity on the suction side expands and then the liquid flows out of the discharge as the cavity collapses providing water in a pail.

6 0
3 years ago
Okay i'm totally stuck and nobody I know really gets it either, so i've turned to Yahoo for help :)
OlgaM077 [116]

Here is the rule for see-saws here on Earth, and there is no reason
to expect that it doesn't work exactly the same anywhere else:

                     (weight) x (distance from the pivot) <u>on one side</u>
is equal to
                     (weight) x (distance from the pivot) <u>on the other side</u>.

That's why, when Dad and Tiny Tommy get on the see-saw, Dad sits
closer to the pivot and Tiny Tommy sits farther away from it.

       (Dad's weight) x (short length) = (Tiny Tommy's weight) x (longer length).


So now we come to the strange beings on the alien planet.
There are three choices right away that both work:

<u>#1).</u>
(400 N) in the middle-seat, facing (200 N) in the end-seat.

       (400) x (1)  =    (200) x (2)

<u>#2).</u>
(200 N) in the middle-seat, facing (100 N) in the end-seat.

       (200) x (1)  =    (100) x (2)

<u>#3).</u>

On one side:  (300 N) in the end-seat       (300) x (2) = <u>600</u>

On the other side:
                      (400 N) in the middle-seat  (400) x (1) = 400
           and     (100 N) in the end-seat      (100) x (2) = 200
                                                    Total . . . . . . . . . . . . <u>600</u> 


These are the only ones to be identified at Harvard . . . . . . .
There may be many others but they haven't been discarvard.


5 0
3 years ago
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Which situation describes a system with decreasing gravitational potential energy?
lord [1]

Answer: a boy jumping down

6 0
3 years ago
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