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2 years ago

What type of data allows geologists to know what rock layers lie underneath Minnesota?

1 answer:

5 0

The answer is well log data, it is a detailed log of information taken from a borehole which geologist used to study geological formations of the earth's layer taken from samples returned from the borehole which was dugged.

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The gravitational potential is a distance z=0.17 m away from a distribution of mass that has the following equation:

sveta [45]

gravitational potential is given as

$V = \frac{GM}{R^2}(R^2 + Z^2)^0.5$

$E = -\frac{dV}{dz}$

$E = -\frac{GM}{R^2}\frac{d}{dz}(R^2+z^2)^0.5$

$E = -\frac{GM}{R^2}*0.5(R^2+z^2)^-0.5*2z$

$E = -\frac{GM*z}{R^2*(R^2 + z^2)^0.5}$

now plug in all values given

M = 110 kg

R = 0.55 m

z = 0.17 m

$E = -\frac{6.67 * 10^{-11}* 110*0.17}{0.55^2*(0.55^2 + 0.17^2)^0.5}$

$E = 7.16 * 10^{-9} N/kg$

so above is the field intensity

4 0

2 years ago

Alpha Particles

UNO [17]

Alpha > Beta > Gamma

Explanation:

Alpha particles are the heaviest radiation whereas gamma rays are the lightest.

An alpha particle closely resembles a helium particle.

Beta particles are similar to electrons in nature

Gamma rays have no weight. They are just rays.

Alpha particles have a mass of 4.0012amu which is that of helium

Beta particles have a mass of 5.5 x 10⁻⁴ amu

Gamma rays have no mass.

Learn more:

Electromagnetic radiations brainly.com/question/6818046

#learnwithBrainly

7 0

2 years ago

Read 2 more answers

Whic ones are true and false?

Tju [1.3M]

Answer:

I think option a is true

6 0

2 years ago

Read 2 more answers

An object's angular momentum changes by 10 kg-m2/s in 2.0 s. What magnitude average torque acted on this object? *

Colt1911 [192]

Answer:

$\tau=5N\cdot m$

Explanation:

The first derivative of the angular momentum with respect to time is defined as the magnitude of the average torque acting on the particle:

$\frac{dL}{dt}=\tau$

So, we calculate the magnitude of the average torque, dividing the change of the angular momemtum into the time:

$\tau=\frac{\Delta L}{\Delta t}\\\tau=\frac{10\frac{kg\cdot m^2}{s}}{2s}\\\tau=5N\cdot m$

5 0

3 years ago

riders on the tower of doom, an amusement park ride, experience 2.0 s of free fall, after which they are slowed to a stop in 0.5

Rainbow [258]

By Newton's second law, the apparent weight of rider coming at rest is <u>3548 N</u>.

According to formula, v = u + at

a = 39.2 m/ $s^{2}$

Force, F = ma

F = m(a+g)

F = apparent weight

m = mass, given = 65 kg

a = acceleration, given = 39.2 m/ $s^{2}$

g = 9.8 m/ $s^{2}$

Put these values in formula, F = m(a+g)

F = 65(39.2+9.8)

F = 3548 N

Therefore, the apparent weight of rider coming at rest is <u>3548 N</u>.

Learn more about apparent weight here:- brainly.com/question/24897276

#SPJ4

6 0

1 year ago