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Alla [95]
3 years ago
5

Which of the following is NOT a criteria for a celestial object to be a planet?

Physics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

The option which is not a criteria for a celestial object to be a planet is;

The object must be massive enough have a gravitational pull on the Sun

Explanation:

There are three criteria for a celestial object to be classified as a planet including;

1) The object's orbit is around the Sun

2) The shape of the object is nearly round due to its mass which is capable of assuming hydrostatic equilibrium

3) Other smaller objects in the neighborhood around the object has been cleared by the object

Therefore, the option which is not a criteria for a celestial object to be a planet is that it must be massive enough to have a gravitational pull on the Sun as every two objects in the Universe share a common gravitational pull according to Newton's Law of Gravitation.

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What are 5 ways to conserve energy at school?
Gnoma [55]
1. turn off lights in classrooms when not in use.
2. turn off all computers when not in use.
3.use a small amount of water when washing your hands.
4. Don't charge your cell phones during class.
5. open windows instead of using air conditioner
5 0
3 years ago
In reaching her destination, a backpacker walks with an average velocity of 1.22 m/s, due west. This average velocity results be
Vinvika [58]
Wow! 2.95m/s is a mighty fast pace for a backpacker. Must have one of those Star Wars anti-gravity packs. Also, I would be curious as to why she passed her destination and then walked back. 
<span>Anyway, it goes like this: </span>
<span>Say the time walking east is 't', and the total time is 'T'. </span>
<span>Then 5340 m + .511 t = 1.43 T </span>
<span>(This assumes that velocity is positive in both directions) </span>
<span>Two unknowns in one equation. But you also know that the time spent walking west is </span>
<span>5340m/ 2.95m/s = 1810 sec. </span>
<span>and the total time T = 1810 +t </span>
<span>Substitute this into the first equation, and you can solve for t = 3092 sec. </span>
<span>Then T = 4902 sec. and distance walked east is .511t = 1580m.</span>
8 0
4 years ago
Frequency definition class 9 sub science​
tia_tia [17]

Explanation:

1.

the rate at which something occurs over a particular period of time or in a given sample.

"an increase in the frequency of accidents due to increased overtime"

2.

the rate per second of a vibration constituting a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light).

"different thicknesses of glass will absorb different frequencies of sound"

7 0
4 years ago
Read 2 more answers
A hollow cylinder that is rolling without slipping is given a velocity of 5.0 m/s and rolls up an incline to a vertical height o
inysia [295]

Answer:

The hollow cylinder rolled up the inclined plane by 1.91 m

Explanation:

From the principle of conservation of mechanical energy, total kinetic energy = total potential energy

M.E_T = \frac{1}{2}mv^2 + \frac{1}{2} I \omega^2 + mgh

The total energy at the bottom of the inclined plane = total energy at the top of the inclined plane.

\frac{1}{2}mv_i^2 + \frac{1}{2} I \omega_i^2 + mg(0) =  \frac{1}{2}mv_f^2 + \frac{1}{2} I \omega_f^2 + mgh

moment of inertia, I, of a hollow cylinder = ¹/₂mr²

substitute for I in the equation above;

\frac{1}{2}mv_i^2 + \frac{1}{2} (\frac{1}{2}mr^2  \omega_i^2) =  \frac{1}{2}mv_f^2 + \frac{1}{2} (\frac{1}{2}mr^2  \omega_f^2) + mgh\\\\ but \ v = r \omega\\\\\frac{1}{2}mv_i^2 + \frac{1}{2} (\frac{1}{2}m v_i^2  ) =  \frac{1}{2}mv_f^2 + \frac{1}{2} (\frac{1}{2}m v_f^2) + mgh\\\\\frac{1}{2}mv_i^2 +\frac{1}{4}mv_i^2 = \frac{1}{2}mv_f^2 +\frac{1}{4}mv_f^2 +mgh\\\\\frac{3}{4}mv_i^2 = \frac{3}{4}mv_f^2 +mgh\\\\mgh = \frac{3}{4}mv_i^2 -  \frac{3}{4}mv_f^2\\\\gh = \frac{3}{4}v_i^2 -  \frac{3}{4}v_f^2\\\\

h = \frac{3}{4g}(v_1^2 -v_f^2)

given;

v₁ = 5.0 m/s

vf = 0

g = 9.8 m/s²

h = \frac{3}{4g}(v_1^2 -v_f^2) =\frac{3}{4*9.8}(5^2 -0) = 1.91 \ m

Therefore, the hollow cylinder rolled up the inclined plane by 1.91 m

5 0
3 years ago
What is the magnitude of the kinetic frictional force?<br> 25 N<br> 125 N<br> 375 N<br> 500 N
Firlakuza [10]

Answer:25N

Explanation:

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