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3 years ago

Which of the following is NOT a criteria for a celestial object to be a planet?

Physics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

The option which is not a criteria for a celestial object to be a planet is;

The object must be massive enough have a gravitational pull on the Sun

Explanation:

There are three criteria for a celestial object to be classified as a planet including;

1) The object's orbit is around the Sun

2) The shape of the object is nearly round due to its mass which is capable of assuming hydrostatic equilibrium

3) Other smaller objects in the neighborhood around the object has been cleared by the object

Therefore, the option which is not a criteria for a celestial object to be a planet is that it must be massive enough to have a gravitational pull on the Sun as every two objects in the Universe share a common gravitational pull according to Newton's Law of Gravitation.

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Two identical objects (A, B) travel circles of the same radius, but object A completes three times as many rotations as object B

malfutka [58]

Answer:

a) One-ninth the force acting on object A.

Explanation:

First, we derive an expression for the centripetal force acting on both objects.

For object A, centripetal force is:

$F_A = \frac{m{v_A}^2}{r}$

For object B, centripetal force is:

$F_B = \frac{m{v_B}^2}{r}$

We are given that they have the same mass and they move in circles of the same radius.

If object A completes three times as many rotations as object B, then, object must have 3 times the speed of object B.

Hence:

${v_A} = 3*{v_B}$

Therefore, $F_A$ becomes:

$F_A = \frac{m({3*v_B}^{2} )}{r}\\\\\\F_A = \frac{9m{v_B}^{2}}{r}$

$F_A = 9F_B$

=> $F_B = \frac{1}{9} F_A$

Therefore, the net centripetal force acting on object B is one-ninth of the force acting on object A.

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What is responsible for the hole in the ozone layer?

Vaselesa [24]

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If a pitcher throws a baseball 10 m in 30 seconds - what would be the average speed?

allsm [11]

Answer:

0.333 m/s

Explanation:

avg speed= (total distance)/(total time)

10m/30s

0.333 m/s

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