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Rudik [331]
3 years ago
5

__________ is designed to protect you from injuries to your head, face, eyes, ears, hands, feet, respiratory tract, and body. A.

Occupational Safety and Health Administration B. Personal Protective Equipment (PPE) C. Safety Guards
Chemistry
2 answers:
marishachu [46]3 years ago
5 0
<h2>Answer:</h2>

Option B is the correct answer.

B. Personal Protective Equipment (PPE)

<h2>Explanation:</h2>

Personal protective equipment are of many purposes e.g for Respiratory protection, Eye protection, Hearing protection Hand protection. So there are many equipment that are designed for the personal protection of scientists and humans.

Nadusha1986 [10]3 years ago
3 0
_________ is designed to protect you from injuries to your head, face, eyes, ears, hands, feet, respiratory tract, and body
the answer to this question, is B personal protective equipment
hope this helps :D
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8 0
3 years ago
Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0
olya-2409 [2.1K]

Answer:

pH=-1.37

Explanation:

We are given that 25 mL of 0.10 M CH_3COOH is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of CH_3COOH=25mL=0.025 L

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL=\frac{35}{1000}=0.035 L

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of CH_3COOH=0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+=0.10\times 0.025=0.0025 moles

Number of moles of OH^-=0.10\times 0.01=0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+=\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L

pH=-log [H+]=-log [4.28\times 10^{-2}]=-log4.28+2 log 10=-0.631+2

pH=-1.37

6 0
3 years ago
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