I think not because a square has four sides and a triangle has three.
Answer:
Solutions are 2, -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i
or 2, -1 + 1.58 i and -1 - 1.58i
(where the last 2 are equal to nearest hundredth).
Step-by-step explanation:
The real solution is x = 2:-
x^3 - 8 = 0
x^3 = 8
x = cube root of 8 = 2
Note that a cubic equation must have a total of 3 roots ( real and complex in this case). We can find the 2 complex roots by using the following identity:-
a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here a = x and b = 2 so we have
(x - 2)(x^2 + 2x + 4) = 0
To find the complex roots we solve x^2 + 2x + 4 = 0:-
Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2
= -1 +/- (sqrt( -10)) / 2
= -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i
Answer:
0
Step-by-step explanation:
Answer:
2x + 20 = 3x-10
2x -3x = -20-10
-x = -30
x= 30
Checking part:
2x+20 = 2(30) +20 = 60+20 = 80
3x-10 = 3(30) - 10 = 90-10 = 80
Hence, the final answer is x = 30.
Step-by-step explanation:
Answer:
A-1
Step-by-step explanation:
It perfectly represents the scenario.
