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I am Lyosha [343]
3 years ago
5

SELECT TWO MIXED NUMBERS WHOSE ESTIMATED DIFFERENCE IS 1. JUSTIFY YOUR SELECTION BY ROUNDING

Mathematics
1 answer:
Amanda [17]3 years ago
6 0
3 3/4 and 2 3/4, 4-3 is 1
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. Which inequality is shown in the graph below? O 1 ys-X+ 1 2 ys-x+1 8 O 1 y-X+1 2 yz x+1 4 2 -8-6420 -2 2 4 6 8 1 y> X+1 2 o
melisa1 [442]

Answer:

the answer is the last one 1 -6 -8 O 1 y =X 1 2 y

Step-by-step explanation:

8 0
3 years ago
Directions: Follow the instructions for the following inequalities. 1. 4<7 Multiply both sides by 7 , then by 6, then by 3, t
worty [1.4K]

In the given question, we have to perform this experiment and test if the inequality is true or not.

Adding the same value to both sides of the inequality will not change the inequality sign

<h3>Inequality</h3>

data;

  • 4 < 7
  • 11 > - 2
  • -4 < - 2
  • -8 < 8

In the first case, we would do follow the process

6 * 7 * 4 < 7 * 7 * 6\\168 < 294

In the second case;

11 > - 2\\\\5 + 11 > -2 + 5\\3 + 16 > 3 + 3\\4+ 19 > 6 + 4\\23 > 10

In all the scenarios, the operations did not affect the inequality sign because we are doing it equally to all side and at the end of the day nullifies each other.

Learn more on inequality here;

brainly.com/question/24372553

#SPJ1

4 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
diamong [38]

Answer:

 A-2, B-DNE*, C-3, D-DNE, E-4, F-1

---------------------

The first attachment shows the solutions to A and C.

The second attachment shows the solutions to E and F.

There are no real number solutions to systems B and D.

_____

In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.

A.

 (3-x) +12 = x^2 +x

 15 = x^2 + 2x

 16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root

 ±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A

__

B.

 (x -1) -15 = x^2 +4x

 -16 = x^2 +3x

 -13.75 = x^2 +3x +2.25 = (x +1.5)^2

roots are complex: -1.5 ±i√13.75

__

C.

 (1-2x) +5 = x^2 -3x

 6 = x^2 -x

 6.25 = x^2 -x + .25 = (x -.5)^2

 ±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C

__

remaining problems are done in a similar way.

_____

* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.

---------------------

<em>Hope this helps!</em>

<em />

<u>Brainliest would be great!</u>

<u />

---------------------

<em><u>With all care,</u></em>

<em><u>07x12!</u></em>

4 0
4 years ago
If 2 angles are both vertical and supplementary, then the angles are
Karo-lina-s [1.5K]
They are both right angles. If they are vertical they are congruent, and if they are supplementary they add to 180. Only two right angles would satisfy both conditions.
7 0
3 years ago
Name three decimals between 16.4 and 16.5. Draw a number line estimating the placement off all five decimals.
Doss [256]
16.42 and 16.43 and 16.44 It ranges from any numbers between 16.40-16.50

Remember that there is an imaginary 0 next to the tenths place.
7 0
3 years ago
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