Answer:
<h2><em>
34.46m</em></h2>
Explanation:
Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;
v is the final velocity of the bicyclist = 26m/s
u is the initial velocity of the bicyclist = 0m/s
a is the acceleration due to gravity = 9.81m/s
s is the distance covered during travel
Substitute the given parameters into the formula above to get the distance traveled
26² = 0² + 2(9.81)s
676 = 19.62s
Divide both sides by 19.62
676/19.62 = 19.62s/19.62
s = 34.46m
<em>The distance traveled by the bicyclist during the race is 34.46m</em>
Answer:
450N
Explanation:
Impulse = mv ---> 180kgm/s = (0.5kg)v
v = 360 m/s
Acceleration = v/t ---> a = (360 m/s)/(0.4s) = 900 m/s^2
Force = ma ---> F = (0.5kg)(900 m/s^2) = 450N
Brainliest?
The answers to question 4 d
