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andrew-mc [135]
3 years ago
14

Why do we break up angled forces into components? How does that help us solve force problems?

Physics
1 answer:
galina1969 [7]3 years ago
7 0

Answer:

As the angle is increased, the acceleration of the object is increased. The explanation of this relates to the components that we have been drawing. As the angle increases, the component of force parallel to the incline increases and the component of force perpendicular to the incline decreases.

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A skateboarder is moving 5.25 m/s when he starts to roll up a frictionless hill. How much higher is he when his velocity has red
Taya2010 [7]
Mechanical energy E = mgh + 1/2mv²

When he starts, let h = 0 ⇒ E₁ = 1/2mv₁²
When he reaches height h ⇒ E₂ = mgh + 1/2mv₂²

Without friction, energy is conserved at all times.

E₁ = E₂
     ↓
1/2mv₁² = mgh + 1/2mv₂²
     ↓
1/2v₁² = gh + 1/2v₂²
     ↓
gh = 1/2(v₁² - v₂²)
    ↓
h = (v₁² - v₂²) / (2g)


5 0
4 years ago
Read 2 more answers
Any clue on this one
aniked [119]
3rd one I believe so
6 0
4 years ago
Your outlets at home are rated at 120 V, i.e. the two prongs have on average a potential difference of 120V. If you transfer 2.7
hodyreva [135]

Answer:

E =230.4 MJ

Explanation:

As 1 mole of electron =  6X 10^23 particles.

charge of an electron is 1.6 X 10 ^-19 C

Finding Charge:

(6X10^23 ) (2.7)(1.6X10^-19 C)

i.e. 192 K C

now  to find the energy released from electrons

V=E/q

E=V X q

i.e E = 120 V X 192 K C

E =230.4 MJ

4 0
3 years ago
5. Which of the following is velocity? *
ivann1987 [24]
A. 20m/s because the unit for velocity is m/s
3 0
3 years ago
(b) The density of aluminum is 2.70 g/cm3. The thickness of a rectangular sheet of aluminum foil varies
vekshin1

Answer:

(i) 22.48 cm^3

(ii) 1.5 mm

Explanation:

Let t be the average thickness of the sheet.

Given that:

Density of the aluminum sheet is 2.70 g/cm^3

Mass of sheet = 60.7 g

Length of sheet  = 50.0 cm

Width of sheet  = 30.0 cm

(i) Using, Density=Mass/Volume

\Rightarrow \text{Volume}=\frac{\text{Mass}}{\text{Density}}

\Rightarrow \text{Volume}=\frac{60.7}{2.7}=22.48 cm^3

Hence, the volume of the sheet is 22.48 cm^3.

(ii) Now, as this aluminum sheet is in the shape of a cuboid, so the volume of the sheet is

\text{Volume}=\text{Length}\times\text{Width}\times\text{Thickness}

\Rightarrow 22.48=50\times 30 \times w

\Rightarrow w=\frac{22.48}{50\times 30}=0.015 cm

Hence, the average thickness of the sheet is 1.5 mm.

6 0
4 years ago
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