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Rama09 [41]
4 years ago
14

A 4,000-kg car traveling at 20m/s hits a wall with a force of 80,000 N and comes to a stop. What was the impact time?

Physics
1 answer:
Nookie1986 [14]4 years ago
7 0
Rate of change of momentum = impact force
(m*v-m*u)/t = F
4000*20/t = 80000 (note: v is zero as it stopped)
<span>soo, t = 1 sec</span>
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Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

         I = F t = Δp

in this case the final velocity is zero

        F t = 0 -m v₀

        F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

        F₁ = -p₀ / 0.1

        F₁ = - 10 p₀

barrier collapses

         F₂ = -p₀ / 1

let's look for the relationship of the forces

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what does the density of an object tell you about the molecular arrangement of the atoms in an object
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1. What distance is required for a train to stop if its initial velocity is 23 m/s and its
Irina-Kira [14]

Answer:

x=?

dt=?

vi=23m/s

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d=0.25m/s^2

time =

vf=vi+d: 0=23m/s+(0.25m/s^2)t

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displacement=

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Explanation:

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6 0
3 years ago
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